Answer:
litrally I don't understand what you are telling
Answer:
There is some mistake in the question, because the solutions are x = -1.445 and x = -34.555
Step-by-step explanation:
Given the functions:
f(x) = x² + 4x + 10
g(x) = -32x - 40
we want to find the points at which f(x) = g(x).
x² + 4x + 10 = -32x - 40
x² + 4x + 10 + 32x + 40 = 0
x² + 36x + 50 = 0
Using quadratic formula:
![x = \frac{-b \pm \sqrt{b^2-4(a)(c)}}{2(a)}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B-b%20%5Cpm%20%5Csqrt%7Bb%5E2-4%28a%29%28c%29%7D%7D%7B2%28a%29%7D%20)
![x = \frac{-36 \pm \sqrt{36^2-4(1)(50)}}{2(1)}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B-36%20%5Cpm%20%5Csqrt%7B36%5E2-4%281%29%2850%29%7D%7D%7B2%281%29%7D%20)
![x = \frac{-36 \pm 33.11}{2}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B-36%20%5Cpm%2033.11%7D%7B2%7D%20)
![x_1 = \frac{-36 + 33.11}{2}](https://tex.z-dn.net/?f=x_1%20%3D%20%5Cfrac%7B-36%20%2B%2033.11%7D%7B2%7D%20)
![x_1 = -1.445](https://tex.z-dn.net/?f=x_1%20%3D%20-1.445%20)
![x_2 = \frac{-36 - 33.11}{2}](https://tex.z-dn.net/?f=x_2%20%3D%20%5Cfrac%7B-36%20-%2033.11%7D%7B2%7D%20)
![x_2 = -34.555](https://tex.z-dn.net/?f=x_2%20%3D%20-34.555)
Answer:
26,577
Step-by-step explanation: