Answer:
Step-by-step explanation:
412.65
https://www.learncbse.in/ncert-solutions-for-class-7-maths/
a2 =14
a4 = 22
a11 = 50
an = 10 + (n-1) *4
n is the term number
Let n =2
a2 = 10 +(2-1)*4 =10 +(1)*4 = 14
Let n =4
a4= 10 + (4-1)*4 = 10 *3*4 = 10+12 = 22
Let n = 11
a11 = 10 +(11-1)*4 = 10 *10*4 = 10+40 = 50
