All categories

2 years ago

The units of the subway map below are in miles. Suppose the routes between

Mathematics

1 answer:

levacccp [35]2 years ago

4 0

Distance between Station E and Station G is 8.48 miles (Approx.)

Given:

Distance 3 miles east

Distance 5 miles south

Find:

Distance between Station E and Station G

Computation:

Co-ordinate of Point E = (-3 , 1)

Co-ordinate of Point G is 3 mile east and 5 mile south

So,

Co-ordinate of Point G = (3 , -5)

Distance between two point = √(x2 - x1)² + (y2 - y1)²

So,

Distance between Station E and Station G = √(3 + 3)² + (-5 - 1)²

Distance between Station E and Station G = √(6)² + (-6)²

Distance between Station E and Station G = √36 + 36

Distance between Station E and Station G = √72

Distance between Station E and Station G = 8.48 miles (Approx.)

Learn more:

brainly.com/question/12052812?referrer=searchResults

You might be interested in

If = √ 2 + 2,then p, in terms of a and q, is .... ?

nevsk [136]

Answer:

kjhgikoljuuihg

Step-by-step explanation:

bgkjm

8 0

3 years ago

The revenue, in dollars, of a company that makes toy cars can be modeled by the polynomial 3x2 + 4x – 60. The cost, in dollars,

Tems11 [23]

For this case we have the following quadratic functions:

Revenue: $3x ^ 2 + 4x - 60$

Cost: $3x ^ 2 - x + 200$

Then, we observe that the profit is given by the following mathematical relationship:

$Profit = Revenue - Cost$

Substituting values we have:

$Profit = (3x ^ 2 + 4x - 60) - (3x ^ 2 - x + 200)$

Making the corresponding calculations we have:

$Profit = x ^ 2 (3-3) + x (4 + 1) + (-60-200)\\Profit = 5x - 260$

Answer:

An expression that represents the profit is:

$Profit = 5x - 260$

4 0

3 years ago

Read 2 more answers

Hey what is better butter or cheese? i really need to know its argent!!!

jenyasd209 [6]

Answer:

CHEEEESEEE

Step-by-step explanation:

CHEESEBURGER CHEESECAKE GRILLED CHEESE CHEESESTICKS CHEEESE ENCHILIADAS BROCOLLI CHEESE SOUP CREAMY MAC AND CHEESE POTATO CHEESE BALLS hAM & CHEESE SANDWICH CHEESE EVERYTHING MUAHAHHAHAAHAHAHAAAAAAAAAAAAAAAAAAAAAAAA

7 0

3 years ago

Solve the equation algebraically for all values of X

noname [10]

This is a problem you need to solve using logs. When you use logs you can "pull" the exponents down in front of the log to get a new equation that looks like this: 2x^3 + x^2 log 81 = 6x - 3 log 27. Now divide both sides by log 81 and 6x - 3 simultaneously to get (2x^3 + x^2)/(6x - 3) = (log 27)/(log 81). If you do the log math on the right side you get .75. Now multiply both sides by 6x-3 to get 2x^3+x^2 = .75(6x-3). If you distribute that out on the left side you'll get 2x^3+x^2=4.5x-2.25. Now move everything over to the left side and set the whole thing equal to 0: 2x^3+x^2-4.5x+2.25=0. When you solve for x, you are in essence factoring, so do this by grouping: x^2(2x+1)-2.25(2x+1). Now finally factor out the 2x+1 to get (2x+1)(x^2-2.25). You're not done yet though cuz you need to solve each of those for x: 2x+1=0, and x= -1/2; x^2=2.25, and x=+/- 1.5. So all the values for x here are -1/2, 1.5, and -1.5

5 0

3 years ago

Solve for x, m-3x=2x+p

just olya [345]

m-3x=2x+p
m-x=p (- 2x on both sides)
-x=p-m (- m on both sides)
answer: x=-p+m (divide -1 on both side)

5 0

3 years ago