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Firdavs [7]
2 years ago
10

Round 0.578 to the nearest tenth

Mathematics
2 answers:
Deffense [45]2 years ago
5 0

0.578 rounded to the nearest tenth would be 0.6, since the 7 in the hundredths spot is higher than 5.

noname [10]2 years ago
3 0
The answer is 0.58 because 8 is a bigger number than five and you always round up when the number is larger than five. Therefore you get 0.58
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makayla has $8 to buy at a school fair each ticket cost $1.50 which inequality best represents how many tickets she can buy
ivolga24 [154]

Answer:

Step-by-step explanation:

If she only has $8, she can't spend more than that.  In other words, she can spend ≤$8.

If each ticket is $1.50 per ticket, the inequality that represents how many tickets she can buy if x represents the number of tickets, is

1.5x ≤ 8

6 0
3 years ago
Jordan traveled from Seattle to New York City. First, he flew 1,735 miles from Seattle to Chicago. Then he drove 673 miles from
astra-53 [7]
The answer would D just add 1,735+673=2,408
8 0
3 years ago
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Please help!!!!<br> picture below
Vlada [557]

Answer:

7 ^ 6x + 2 = 7^15

taking log on both the sides

log 7^6x + 2 = log 7^15

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log 7

7 0
1 year ago
593,204 rounded to the nearest million
Romashka [77]

The answer is  1,000,000

6 0
3 years ago
A bin contains 25 light bulbs, 5 of which are in good condition and will function for at least 30 days, 10 of which are partiall
Ira Lisetskai [31]

Answer:

The probability that it will still be working after one week is \frac{1}{5}

Step-by-step explanation:

Given :

Total number of bulbs = 25

Number of bulbs which are good condition and will function for at least 30 days = 5

Number of bulbs which are partially defective and will fail in their second day of use = 10

Number of bulbs which are totally defective and will not light up = 10

To find : What is the probability that it will still be working after one week?

Solution :

First condition is a randomly chosen bulb initially lights,

i.e. Either it is in good condition and partially defective.

Second condition is it will still be working after one week,

i.e. Bulbs which are good condition and will function for at least 30 days

So, favorable outcome is 5

The probability that it will still be working after one week is given by,

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}

\text{Probability}=\frac{5}{25}

\text{Probability}=\frac{1}{5}

5 0
3 years ago
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