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Firdavs [7]
3 years ago
10

Round 0.578 to the nearest tenth

Mathematics
2 answers:
Deffense [45]3 years ago
5 0

0.578 rounded to the nearest tenth would be 0.6, since the 7 in the hundredths spot is higher than 5.

noname [10]3 years ago
3 0
The answer is 0.58 because 8 is a bigger number than five and you always round up when the number is larger than five. Therefore you get 0.58
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f a rectangle has a perimeter of 70, a length of x and a width of x - 9, find the value of the length of the rectangle.
trasher [3.6K]

( x + (x  -  9))  \times 2 = 70 \\( 2x - 9) \times2= 70 \\ 4x - 18 = 70 \\ 4x = 70 + 18 = 88
x =  \frac{88}{4}  = 22
the length is 22


and the width is
22-9=17





good luck
3 0
3 years ago
What is the answer to 10 = -4 x?
lawyer [7]
Solve for x
Divide both sides by -4
X= - 10/4
Now simplify by dividing top and bottom by 2
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6 0
3 years ago
The circumference of F is 120 cm what is the length of DE the minor arc
AfilCa [17]

Answer:

Option E 15 cm

Step-by-step explanation:

we know that

The circumference of a circle subtends a central angle of 360 degrees

so

using proportion

Find out the length of arc DE by a central angle of 45 degrees

Let

x -----> the length of arc DE

\frac{120}{360}=\frac{x}{45}\\\\x=120*45/360\\\\x=15\ cm

7 0
4 years ago
What is the positive solution to this equation?<br><br> 3x^2+16x=112
ikadub [295]

Answer:

This equation is in standard form: ax 1+bx+c=0. Substitute 9 for a, 16 for b, and −112 for c in the quadratic formula 2a−b±b2−4ac.x= 2×9−16± 16^2−4×9(−112)Square 16.x=2×9−16±256−4×9(−112) Multiply −4 times 9.x=2×9−16± 256−36(−112) Multiply −36 times −112.x=2×9−16±256+4032 Add 256 to 4032.x=2×9−16±4288 Take the square root of 4288.x=2×9−16±8+67 Multiply 2 times 9x=18−16±8=67

Step-by-step explanation:

hope this help if not let me know

6 0
3 years ago
Read 2 more answers
The ratio of the width of the rectangle to the height of the rectangle is ?
Karo-lina-s [1.5K]
The area of a rectangle is 108cm (squared. the ratio of the width to the length is 3:4
4 0
3 years ago
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