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padilas [110]
3 years ago
12

50 Points! Question In Image Show ALL Work

Mathematics
1 answer:
Nataliya [291]3 years ago
8 0
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ First identify and assign the variables:

q = number of quarters

d = number of dimes

This is what we know:

q + d = 22

A quarter is 25 cents and a dime is 10 cents

You can write this as:

0.25q + 0.1d = 3.40

Rearrange the first equation for d

d = 22 - q

Substitute this value into the other equation:

0.25q + 0.1(22 - q) = 3.40

Simplify:

0.25q + 2.2 - 0.1q = 3.40

0.15q + 2.2 = 3.4

Subtract 2.2 from both sides:

0.15q = 1.2

Divide both sides by 0.15:

q = 8

Substitute into the first equation:

8 + d = 22

d = 14

Therefore, there are 8 quarters and 14 dimes.

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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The median is 155

Step-by-step explanation:

You get the numbers from least to greatest then the middle number is your median.

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A parabola with the vertex at (1.5, 12.5) inscribes a segment of length 5 on x-axis. What is the area of the triangle formed by
damaskus [11]

Answer:

  20 units²

Step-by-step explanation:

The x-intercepts are symmetrically located around the x-coordinate of the vertex, so are at

  1.5 ± 5/2 = {-1, 4}

Using one of these we can find the unknown parameter "a" in the parabola's equation (in vertex form) ...

  0 = a(4 -1.5)² +12.5

  0 = 6.25a +12.5 . . . . . simplify

  0 = a +2 . . . . . . . . . . . divide by 6.25

  -2 = a

Then the standard-form equation of the parabola is ...

  y = -2(x -1.5)² +12.5 = -2(x² -3x +2.25) +12.5

  y = -2x² +6x +8

This tells us the y-intercept is 8. Then the relevant triangle has a base of 5 units and a height of 8. Its area is given by the formula ...

  A = (1/2)bh = (1/2)(5)(8) = 20 . . . . units²

5 0
3 years ago
List the factors in decimals in order from least to greatest 0.5 3/16 0.75. 5/48
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5/48
3/16
0.5
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To divide a decimal number by 1,000, move the decimal point _____.
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Each of a group of 20 intermediate tennis players is given two rackets, one having nylon strings and the other synthetic gut str
sergeinik [125]

Answer:

Find answers below

Step-by-step explanation:

H0: P <= 0.5

Ha: P > 0.5

, the number who prefer gut strings is <= a number or the test tends towards the  left-tailed.

{0,1,2,3,4,5} ;  

{15,16,17,18,19,20} is a right-tailed test and not appropriate for H0:

{ 0,1,2,3,17,18,19,20} is two-tailed and not appropriate for H0:

b)

Does the region specify a level .05 test? No

 

P = proportion who prefer gut strings to nylon

P = X /20

Assume alpha = 0.05

z(alpha) = -1.645

Reject if (x/20 - 0.5) / sqrt[ (0.5)(0.5)/20 ] < -1.645

Reject if (x/20 - 0.5) <  < (-1.645) sqrt ( (0.5)(0.5)/20 )

Reject if x/20   < (-1.645) sqrt ( (0.5)(0.5)/20 ) + 0.5

Reject if x/20   < 0.316

Reject if x   < (0.316)(20) = 6.32

{0,1,2,3,4,5,6} is the region for the best level 0.05 test

c)

According to (a),  reject H0 if x <= 5

P( Type II error) = P( do not reject H0/ when Ha is true)

P( Type II error) = P( x > 5/ P=0.6)

x ---p(x)

6  0.004854  0.998388  

7  0.014563    

8  0.035497  

9  0.070995  

10  0.117142  

11  0.159738  

12  0.179706  

13  0.165882  

14  0.124412  

15  0.074647  

16  0.034991  

17  0.012350  

18  0.003087  

19  0.000487  

20  0.000037  

add: 0.9984 --  proba bility of a type II error

Assuming P=0.8

P( Type II error) = P( x > 5/ P=0.8)

6  0.000002  1.000000  

7  0.000013  

8  0.000087  

9  0.000462  

10  0.002031  

11  0.007387  

12  0.022161  

13  0.054550  

14  0.109100  

15  0.174560  

16  0.218199  

17  0.205364  

18  0.136909  

19  0.057646  

20  0.011529  

add: 1.0000  probability of a type II error

d)

P( x <= 13) =  

0  0.000001  

1  0.000019  

2  0.000181  

3  0.001087  

4  0.004621  

5  0.014786  

6  0.036964  

7  0.073929  

8  0.120134  

9  0.160179  

10  0.176197  

11  0.160179  

12  0.120134  

13  0.073929  

add: 0.9423 < 0.10 ,  H0 cannot be rejected

5 0
3 years ago
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