Find the product . Write your answer in exponential form 8^-2•8^-9

Mathematics

1 answer:

11Alexandr11 [23.1K]3 years ago

6 0

Answer:

8^-11

Step-by-step explanation:

The applicable rule of exponents is ...

(a^b)(a^c) = a^(b+c)

Then we have ...

(8^(-2))·(8^(-9)) = 8^(-2-9) = 8^-11

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nadezda [96]

Answer:

Step-by-step explanation:

The quadratic formula:

$\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

where a is the coefficient of $x^2$ , b being the coefficient of $x$ and c being the constant.

Plug in the values:

$\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:2\cdot \:5}}{2\cdot \:2}$

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3 years ago

Read 2 more answers

The explicit formula for a sequence is<br> an=−2+3/2(n−1)<br> What is the 21st term of the sequence?

Anni [7]

Step-by-step explanation:

From the given question it appears that (n-1) is in the numerator's place, if it is so, then let us solve it.

$a_n = - 2 + \frac{3}{2}(n - 1) \\ \\ \therefore \: a_{21} = - 2 + \frac{3}{2} (21 - 1) \\ \\ \therefore \: a_{21} = - 2 + \frac{3}{2 } \times \: 20\\ \\ \therefore \: a_{21} = - 2 + 3 \times \: 10 \\ \\ \therefore \: a_{21} = { -2 + 30} \\ \\ \therefore \: a_{21} = 28 \\ \\ \huge \red{ \boxed{\therefore \: a_{21} = 28} } \\ \\$