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maw [93]
2 years ago
5

Perform the indicated operation g(x)=x^3+5x and f(x)=2x-2 Find (g o f)(x)

Mathematics
1 answer:
Blababa [14]2 years ago
4 0

Answer:

  g(f(x)) = 8x^3-24x^2+34x-18

Step-by-step explanation:

The composition is ...

  (g\circ f)(x)=g(f(x))=g(2x-2)\\\\=(2x-2)^3+5(2x-2)\\\\=(2x)^3 +3(-2)(2x)^2+3(-2)^2(2x)+(-2)^3+10x-10\\\\=8x^3-24x^2 +24x-8+10x-10\\\\\boxed{(g\circ f)(x)=8x^3-24x^2+34x-18}

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Find the 78th term of the arithmetic sequence –4,-2,0,...
MArishka [77]

The number is increasing by 2 every time.

78 x 2 = 156

-4 + 156 = 152

The 78th term is 152

8 0
2 years ago
If bolt thread length is normally distributed, what is the probability that the thread length of a randomly selected bolt is Wit
KatRina [158]

Answer:

a) 0.5762

b) 0.0214

c) 0.2718

Step-by-step explanation:

It is given that lengths of the bolt thread are normally distributed. So in order to find the required probability we can use the concept of z distribution and z scores.

Part a) Probability that length is within 0.8 SDs of the mean

We have to calculate the probability that the length of a bolt thread is within 0.8 standard deviations of the mean. Recall that a z- score tells us that how many standard deviations away a value is from the mean. So, indirectly we are given the z-scores here.

Within 0.8 SDs of the mean, means from a score of -0.8  to +0.8. i.e. we have to calculate:

P(-0.8 < z < 0.8)

We can find these values from the z table.

P(-0.8 < z < 0.8) = P(z < 0.8) - P(z < -0.8)

= 0.7881 - 0.2119

= 0.5762

Thus, the probability that the thread length of a randomly selected bolt is within 0.8 SDs of its mean value is 0.5762

Part b) Probability that length is farther than 2.3 SDs from the mean

As mentioned in previous part, 2.3 SDs means a z-score of 2.3.

2.3 Standard Deviations farther from the mean, means the probability that z scores is lesser than - 2.3 or greater than 2.3

i.e. we have to calculate:

P(z < -2.3 or z > 2.3)

According to the symmetry rules of z-distribution:

P(z < -2.3 or z > 2.3) = 1 - P(-2.3 < z < 2.3)

We can calculate P(-2.3 < z < 2.3) from the z-table, which comes out to be 0.9786. So,

P(z < -2.3 or z > 2.3) = 1 - 0.9786

= 0.0214

Thus, the probability that a bolt length is 2.3 SDs farther from the mean is 0.0214

Part c) Probability that length is between 1 and 2 SDs from the mean value

Between 1 and 2 SDs from the mean value can occur both above the mean and below the mean.

For above the mean: between 1 and 2 SDs means between the z scores 1 and 2

For below the mean: between 1 and 2 SDs means between the z scores -2 and -1

i.e. we have to find:

P( 1 < z < 2) + P(-2 < z < -1)

According to the symmetry rules of z distribution:

P( 1 < z < 2) + P(-2 < z < -1) = 2P(1 < z < 2)

We can calculate P(1 < z < 2) from the z tables, which comes out to be: 0.1359

So,

P( 1 < z < 2) + P(-2 < z < -1) = 2 x 0.1359

= 0.2718

Thus, the probability that the bolt length is between 1 and 2 SDs from its mean value is 0.2718

4 0
3 years ago
Pleas help meeeeeeeeeeeeeeeeeee
lisabon 2012 [21]

Answer:

.

Step-by-step explanation:

.

4 0
3 years ago
Can i have help on this pls can you classify 17.3 in as many groups as possible
PIT_PIT [208]

It can go into the group integers, as well as rational numbers.

Hope this helps you! Happy thanksgiving, here's a turkey!

8 0
3 years ago
Solve sin x - (3sin x-1) = 0
soldi70 [24.7K]

Answer:

\large\boxed{x=\dfrac{\pi}{6}+2k\pi\ \vee\ x=\dfrac{5\pi}{6}+2k\pi,\ k\in\mathbb{Z}}

Step-by-step explanation:

\sin x-(3\sin x-1)=0\\\\\sin x-3\sin x+1=0\qquad\text{subtract 1 from both sides}\\\\-2\sin x=-1\qquad\text{divide both sides by 2}\\\\\sin x=\dfrac{1}{2}\Rightarrow x=\dfrac{\pi}{6}+2k\pi\ \vee\ x=\dfrac{5\pi}{6}+2k\pi,\ k\in\mathbb{Z}

\text{Equation:}\\\\\sin x=a\\\\\text{has solutions}\\\\x=\theta+2k\pi\ \vee\ x=(\pi-\theta)+2k\pi\\\\\text{Why}\ 2k\pi?\\\text{Because the sine function has a period of}\ 2\pi.

\text{look at the table}\\\\\sin x=\dfrac{1}{2}\to x=\dfrac{\pi}{6}\ \vee\ x=\pi-\dfrac{\pi}{6}=\dfrac{5\pi}{6}

\text{Other solution:}\\\\\sin x=\dfrac{1}{2}\Rightarrow x=\sin^{-1}\dfrac{1}{2}\\\\x=\dfrac{\pi}{6}+2k\pi\ \vee\ x=\dfrac{5\pi}{6}+2k\pi

3 0
3 years ago
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