Answer:
See below
Step-by-step explanation:
1: (b+1)*(3b)*(b-5)
(3b^2+3b)(b-5)
3b^3-15b^2+3b^2-10b
3b^3-12b^2-10b
2: πr^ 2(h/3)
π(n-2)^2(12n/3)
π(n-2)(n-2)(12n/3)
π(n^2-2n-2n+4)(12n/3)
π(n^2-4n+4)(12n/3)
π(n^2-4n+4)(4n)
π(4n^3-16n^2+16n)
<em>(I'm not 100% sure with this one)</em>
3: (lwh)/3
((k-2)(2k+3)(3k))/3
((2k^2-4k+3k-6)(3k))/3
(6k^3-12k^2+9k^2-18k)/3
(6k^3-3k^2-18k)/3
2k^3-k^2-6k
Standard form is y=mx+b
<span>y = 2x + 5
</span><span>y = x – 9</span>
Answer:
0, 5x
Step-by-step explanation:
0 in the first box
5x in the second box
x=1
5x+8/2=5x+4
9-4= 5
So now you have 5x=5 divide both sides by 5. And you’ll have x=1
