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Annette [7]
3 years ago
12

Pls help extra points and mark brainlist

Mathematics
1 answer:
STALIN [3.7K]3 years ago
5 0

Answer:

Rock layers only (I think this is correct from the searches I've made)

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Help! I’ll give brainlist!
BigorU [14]

something through 1-10. i think its 7 but i rlly dont know. Sry.

6 0
3 years ago
Grace starts with 100 milligrams of a radioactive substance. The amount of the
love history [14]

Answer:

100 is grace's initial amount. w is how much of the substance is being decrased each week. in ryan's equation, 1 is 100% of the substance, so the initial amount, and 0.4 is the amount that is being decreased.

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
Can u help me on this?
a_sh-v [17]

Answer:

B

Step-by-step explanation:

70-20=50

i don't sure correct or not

7 0
3 years ago
In a canoe race, team a is traveling 6 miles per hour and is 2 miles ahead of team
malfutka [58]
Given that <span>In a canoe race, team a is traveling 6 miles per hour and is 2 miles ahead of team b.

Team b is also traveling 6 miles per hour. The teams continue traveling at their current rates for the remainder of the race.

The system of linear equations that represents this situation is given by

d = 6t + 2
d = 6t
</span>
4 0
3 years ago
Read 2 more answers
Use matrices and elementary row to solve the following system:
LiRa [457]

I assume the first equation is supposed to be

5x-3y+2z=13

and not

5x-3x+2x=4x=13

As an augmented matrix, this system is given by

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\4&-2&4&12\end{array}\right]

Multiply through row 3 by 1/2:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\2&-1&2&6\end{array}\right]

Add -1(row 2) to row 3:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&5&5\end{array}\right]

Multiply through row 3 by 1/5:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&1&1\end{array}\right]

Add -2(row 3) to row 1, and add 3(row 3) to row 2:

\left[\begin{array}{ccc|c}5&-3&0&11\\2&-1&0&4\\0&0&1&1\end{array}\right]

Add -3(row 2) to row 1:

\left[\begin{array}{ccc|c}-1&0&0&-1\\2&-1&0&4\\0&0&1&1\end{array}\right]

Multiply through row 1 by -1:

\left[\begin{array}{ccc|c}1&0&0&1\\2&-1&0&4\\0&0&1&1\end{array}\right]

Add -2(row 1) to row 2:

\left[\begin{array}{ccc|c}1&0&0&1\\0&-1&0&2\\0&0&1&1\end{array}\right]

Multipy through row 2 by -1:

\left[\begin{array}{ccc|c}1&0&0&1\\0&1&0&-2\\0&0&1&1\end{array}\right]

The solution to the system is then

\boxed{x=1,y=-2,z=1}

5 0
3 years ago
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