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Phantasy [73]
3 years ago
8

Set Q contains 20 positive integer values. The smallest value in Set Q is a single digit value and the largest value in Set Q is

a three digit value. What are possible values for the range of Set Q
Mathematics
1 answer:
Lerok [7]3 years ago
5 0

Answer: possible values of Range will be values that are >=91 or <=998

Step-by-step explanation:

Given that :

Set Q contains 20 positive integer values. The smallest value in Set Q is a single digit value and the largest value in Set Q is a three digit value.

Therefore,

given that the smallest value in set Q is a one digit number :

Then lower unit = 1, upper unit = 9( this represents the lowest and highest one digit number)

Also, the largest value in Set Q is a three digit value:

Then lower unit = 100, upper unit = 999 ( this represents the lowest and highest 3 digit numbers).

Therefore, the possible values of the range in SET Q:

The maximum possible range of the values in set Q = (Highest possible three digit value - lowest possible one digit) = (999 - 1) = 998

The least possible range of values in set Q = (lowest possible three digit value - highest possible one digit value) = (100 - 9) = 91

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A factory has three machines making energy drinks. When all three machines are running, 520 drinks are made each hour. When only
Vinil7 [7]

Let A, B and C be the amount machines A, B and C, respectively, produce each hour alone.

With all three machines together produce 520 drinks each hour, we know that the addition of the amount that each produces each hour is equal to 520, that is.

A+B+C=520_{}

Now, similarly, machines A and B produce together 320 drinks each hour, so the sum of the amounts A and B produce each hour is equal to 320, so:

A+B=320

If machine C produce 30 more drinks than B each hour, than the amount of B plus 30 will be the amount of C:

C=B+30

So, we got the system of equations:

\begin{gathered} A+B+C=520 \\ A+B=320 \\ C=B+30 \end{gathered}

To solve, notice that A + B is known, because of the second equation, so we can substitute A + B by 320 in the first equation:

\begin{gathered} (A+B)+C=520 \\ 320+C=520 \\ C=520-320=200 \end{gathered}

Now, we can substitute C into the third equation and solve for B:

\begin{gathered} C=B+30 \\ 200=B+30 \\ B+30=200 \\ B=200-30=170 \end{gathered}

And, finally, we can substitute B into the second equation and solve for A:

\begin{gathered} A+B=320 \\ A+170=320 \\ A=320-170=150 \end{gathered}

Answers:

First box:

A+B+C=520

Second box:

A+B=320

Third box:

C=B+30

Fourth box:

150

3 0
1 year ago
Can someone help me on this question plz
ivolga24 [154]

Answer:

I think its B maybe

I dont know

Step-by-step explanation:

6 0
3 years ago
What is the equation in slope-intercept form of a line parallel to y=−2x+5 and passes through the point (4, 0)?
ser-zykov [4K]

Parallel lines have the same slope

The equation of the line is: y = -2x+8

The equation is given as:

y = -2x + 5

The slope intercept form of an equation is:

y = mx + b

Where:

m \to slope

By comparison,

m = -2

The line is said to be parallel to y = -2x + 5.

This means that the line has a slope of m = -2

The equation of the line is then calculated as:

y = m(x - x_1) + y_1

Where:

(x_1,y_1) = (4,0)

So, we have:

y = m(x - x_1) + y_1

Substitute values for m, x1 and y1

y = -2(x - 4) + 0

y = -2(x - 4)

Open brackets

y = -2x+8

Hence, the equation of the line is: y = -2x+8

See attachment for the graphs of y = -2x+8 and y = -2x + 5

Read more about equations of parallel lines at:

brainly.com/question/402319

8 0
3 years ago
Ill give you BRAINLIST !!!
algol [13]
Answer:

3k^2 -k+5

reason:

when adding two equations together, you combine like terms.
First, add -2 to 7 to get 5
Then, add k, or 1k, to -2k, which gives you -1k, or just -k
3k^2 stays the same because there are no like terms in the other equation to combine it with
8 0
3 years ago
Solve for x:<br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7Bx%2By%7D%20-%5Cfrac%7B3x-3y%7D%7B2x-3y%7D%20%2A%28%5Cfrac%7B
zlopas [31]

Answer:

x = -(3 y)/2

Step-by-step explanation:

Solve for x:

-2 x - 3 y + 3/(x + y) - (3 x - 3 y)/(x^2 - y^2) = 0

Simplify and substitute z = x + y.

-2 x - 3 y + 3/(x + y) - (3 x - 3 y)/(x^2 - y^2) = -y - 2 (x + y)

= -y - 2 z:

-y - 2 z = 0

Multiply both sides by -1:

y + 2 z = 0

Subtract y from both sides:

2 z = -y

Divide both sides by 2:

z = -y/2

Substitute back for z = x + y:

x + y = -y/2

Subtract y from both sides:

Answer:  x = -(3 y)/2


4 0
3 years ago
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