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Marianna [84]
3 years ago
12

Waiting times (in minutes) of customers at the Jefferson Valley Bank (where all customoers enter a single waiting line) and the

Bank of Providence (where customers wait in individual lines at three different teller windows) are listed below. Determine whether there is a difference between the two data sets that is not apparent from a comparison of the measures of center. if so, what is it?
Jefferson (single line): 6.5 6.6 6.7 6.8 7.1 7.3 7.4 7.7 7.7 7.7

Providence (individual lines): 4.2 5.4 5.8 6.2 6.7 7.7 7.7 8.5 9.3 10.0
Mathematics
1 answer:
fiasKO [112]3 years ago
5 0
Sdtgccvhdhdhdhdjccjcjcjcnxb CB CNBC
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A washer and a dryer cost 854$ combined. The washer costs $96 less than the dryer. What is the cost of the dryer
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Answer:

950

Step-by-step explanation:

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If P is the orthocenter of △ABC, AB = 13, BF = 9,and FC = 5.6, find each measure &amp; the perimeter of triangle ABC.
harina [27]

Answer:

Perimeter = 38.6

Step-by-step explanation:

Given

A\ B = 13

B\ F = 9

F\ C = 5.6

Required

Calculate the perimeter of A B C

To calculate the perimeter of A B C, we sum up the sides of the triangle

i.e.

Perimeter = A B + B\ C + A\ C

AB is given in the question already.

So, we need to calculate B F and F C

To solve for BF, we consider triangle B F C

Using Pythagoras Theorem, we have:

B\ C^2 = B\ F^2 + F\ C^2

Substitute values for BF and FC;

B\ C^2 = 9^2 + 5.6^2

B\ C^2 = 81 + 31.36

B\ C^2 = 112.36

B\ C^2= \sqrt{112.36

B\ C = 10.6

Next, we calculate A C.

To calculate A C, we need to calculate A F, considering triangle B F A

Using Pythagoras Theorem, we have:

A\ B^2 = B\ F^2 + A\ F^2

Substitute values for B F and A B;

13^2 = 9^2 + A\ F^2

169= 81 + A\ F^2

A\ F^2 = 169 - 81

A\ F^2 = 88

A\ F = \sqrt{88

A\ F = 9.4

Since F lies on line A C:

A\ C = A\ F + F\ C

A\ C = 9.4 + 5.6

A\ C = 15.0

Recall that:

Perimeter = A\ B + B\ C + A\ C

Perimeter = 13 + 10.6 + 15.0

Perimeter = 38.6

<em>Hence, the perimeter is 38.6</em>

3 0
3 years ago
How many four-character passwords can be formed using the characters A, B, C, 1, 2 if the characters can be repeated
olga55 [171]
<h3>Answer: 625</h3>

Work Shown:

The set {A,B,C,1,2} has five items. There are four slots to fill.

So we have 5^4 = 5*5*5*5 = 625 different possible passwords where the characters can be repeated.

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