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Oxana [17]
3 years ago
12

The coach bought a hamburger and a $1.75 drink for the 10 members of the team. He spent a total of $36.00. Write and nu solve an

equation to determine the price of a hamburger.
Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
7 0

Answer:

1.85

Step-by-step explanation:

equation will be 10(h+1.75)=36

hamburger price is $1.85

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Solve using the pathagorean theorem​
seropon [69]

Answer:

2 sqrt(13)

Step-by-step explanation:

We can find the hypotenuse using the Pythagorean theorem

a^2 + b^2 = c^2  where a and b are the legs and c is the hypotenuse

4^2 + 6^2 = c^2

16+36 = c^2

52 = c^2

Taking the square root of each side

sqrt (52) = c

sqrt(4*13) = c

2 sqrt(13) = c

4 0
2 years ago
Brainliest for a math answer
erastovalidia [21]
Question 5- is 9
question 6- is 9
question 7-is 4
question 8-is 21
Question 9-is 2 
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Tell me if your right ;) 


5 0
3 years ago
Read 2 more answers
A store sells a certain tile for $2 per tile and a pint of paint for $3. A second store sells the same items for $1 per tile and
Paladinen [302]
2t + 3p = 26
t + 4p = 18
8 0
3 years ago
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This means we increase the x value by 1.
velikii [3]

Answer:

The answer is option C, that is, (2,6)

6 0
3 years ago
An insurance company has 10,000 automobile policyholders. The expected yearly claim per policyholder is $240, with a standard de
elena55 [62]

Answer:

almost 0%

Step-by-step explanation:

Given that for an insurance company with 10000 automobile policy holders, the expected yearly claim per policyholder is $240 with a standard deaviation of 800

using normal approximation, the probability that the total yearly claim exceeds $2.7 million is calculated as follows:

Sea sumatoria de x = SUMX, tenemos que:

P (SUMX \geq 2700000) = P(\frac{SUMX - 240*10000}{800 *\sqrt{10000} } \geq \frac{2700000 - 240*10000}{800 *\sqrt{10000} })

= P (z\geq \frac{2700000 - 240*10000}{800 *\sqrt{10000}})

= P (z => 3.75)

= 1 - P ( z < 3.75)

P = 1 - 0.999912

P = 0.000088

Which means that the probability is almost 0%

4 0
3 years ago
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