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4 years ago

I cant figure this out!!!help!!!

Mathematics

1 answer:

victus00 [196]4 years ago

8 0

It's 21, becuase i am bored and don't really know what your question is.

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Draw Y=3x-2 on a grid

Afina-wow [57]

Just subsitute values for x and get values for y
(x,y)
(0,-2)
(1,1)
(-1,-5)
(-2,-8)
here is the graph

8 0

3 years ago

(2 3/8 +1 1/4)+ 2 7/8 using properties of addition

irina1246 [14]

Answer:

Well The answer is: 9

Step-by-step explanation:

(2 3/8 + 11/4)=

(2 + 3) + (3/8 + 3/4)= 6 1/8

(6 1/8 + 2 7/8) =

(6 + 2) + (1/8 + 7/8) = 9

Pls give me brainliest i hope this helped

4 0

3 years ago

A store is giving out cards labelled 1 through 10 when customers enter the store. If the card is an even number, you get a 10% d

frosja888 [35]

Answer:

Relative frequency for each discount :

10% - 0.4925, 20% - 0.3325, 40% - 0.175

Since only 33.25% of customers got 20% discount, it is not an appropriate method.

Step-by-step explanation:

relative frequency = number of frequency/total number of frequency

you can find out relative frequency for each number and add them up to get relative frequencies of discounts.

8 0

2 years ago

Find the volume of the prism.

Rudik [331]

Answer:

216 cubic meters

Step-by-step explanation:

to find the volume of any prism the equation is bh or base times height

the base is a triangle so you find the triangles area and multiply it by the height

8 * 6 * 1/2 = 24

24 * 9 = 216

216 cubic meters

6 0

3 years ago

The length of a rectangle is 5 inches more than its width, x. The area of a rectangle can be represented by the equation x 2 + 5

Arada [10]

Answer:

Width = 15 inches Length = 20 inches

Step-by-step explanation:

The area of a rectangle is calculated using the following formula.

$A = Lx$ (1)

Where L is the length and x is the width of the rectangle

In this case we know that the length of the rectangle is 5 inches greater than its width. This means that:

$L = x + 5$ (2)

Also The area of a rectangle can be represented by the equation $x^2 + 5x = 300$

so to find the width x we solve the equation

$x^2 + 5x -300=0$ (3)

For an equation of the form $ax ^ 2 + bx + c = 0$ the quadratic formula is:

$x=\frac{-b\±\sqrt{b^2-4ac}}{2a}$

In this case note that:

$a=1\\b=5\\c=-300$

Then:

$x=\frac{-5\±\sqrt{(5)^2-4(1)(-300)}}{2(1)}$

$x=\frac{-5\±\sqrt{25+1200}}{2}$

$x=\frac{-5\±\sqrt{1225}}{2}$

$x=\frac{-5\±35}{2}$

$x_1=\frac{-5+35}{2}$ → $x_1=15$

$x_2=\frac{-5-35}{2}$ → $x_2=-20$

We take the positive solution $x=15\ in$

Now we use equation (2) to find L

$L = x + 5$

$L = 15 + 5$

$L = 20\ in$

8 0

4 years ago