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Rainbow [258]
3 years ago
15

Evaluate (1/2)^-2 Please I need help on this

Mathematics
1 answer:
Degger [83]3 years ago
4 0

Answer:

80/7776

Step-by-step explanation:

(1/2)^5 = 1/32

(-2/3)^4 = 16/81

(3/5)^-1 = 5/3

now

1/32 × 16/81 × 5/3

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Solve (1/81)^x*1/243=(1/9)^−3−1 by rewriting each side with a common base.
elena55 [62]

Answer:

x=(243)log_{\frac{1}{81}}[(\frac{1}{81})-1]

Step-by-step explanation:

you have the following formula:

(\frac{1}{81})^{\frac{x}{243}}=(\frac{1}{9})^{-3}-1

To solve this equation you use the following properties:

log_aa^x=x

Thne, by using this propwerty in the equation (1) you obtain for x

log_{(\frac{1}{81})}(\frac{1}{81})^{\frac{x}{243}}=log_{\frac{1}{81}}[(\frac{1}{81})-1]\\\\\frac{x}{243}=log_{\frac{1}{81}}[(\frac{1}{81})-1]\\\\x=(243)log_{\frac{1}{81}}[(\frac{1}{81})-1]

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we know that

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$9.45

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2 years ago
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