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belka [17]
3 years ago
10

Solve for h.3/7 = h/14 - 2/7​

Mathematics
2 answers:
goblinko [34]3 years ago
8 0

Answer:

h = 10

Step-by-step explanation:

3/7 = h/14 - 2/7

h/14 = 3/7 + 2/7

h/14 = 5/7

h = (5/7) × 14

= 10

AleksAgata [21]3 years ago
3 0

Answer:

10

Step-by-step explanation:

Multiplying both sides by 14

2*3=h-(2*2)

6=h-4

h=6+4

h=10

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Which table shows exponential growth decay?
Vanyuwa [196]

Answer:

its going to be the one with the line going down

Step-by-step explanation:

8 0
3 years ago
Perform each indicated operation
MissTica

Answer: \frac{x+6}{x-4}

Step-by-step explanation:

First you need know some general formuals of factorization such as

x^3+y^3=(x+y)(x^2-xy+y^2) so you have x^3+64=X^3+4^3=(x+4)(x^2-4x+4^2)

And, x^2-y^2=(x-y)(x+y) so you have 2x^2-32=2(x^2-16)=2(x^2-4^2)=2(x+4)(x-4)

If you use them, then you can modify your equations such as

\frac{x^3+64}{2x^2-32} ÷ \frac{x^2-4x+16}{2x+12} = \frac{(x+4)(x^2-4x+4^2)}{2(x+4)(x-4)} ÷ \frac{x^2-4x+16}{2(x+6)}  =  \frac{(x+4)(x^2-4x+4^2)}{2(x+4)(x-4)} . \frac{2(x+6)}{{x^2-4x+16}} = \frac{1}{x-4}.\frac{x+6}{1}=\frac{x+6}{x-4}

4 0
3 years ago
Find the domain and range of y=-5x-1
harina [27]

Answer:

  • \mathrm{Domain\:of\:}\:-5x-1\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

  • \mathrm{Range\:of\:}-5x-1:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

Step-by-step explanation:

Finding the domain:

The domain of a function is the set of possible input values for which the function is real and defined.

Given the function

y=-5x-1

The function has no undefined points nor domain constraints. Hence, the domain is

-\infty \:

i.e.

\mathrm{Domain\:of\:}\:-5x-1\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

Finding the range:

The range of a function is the set of possible output values (dependent variable y values) for which a function is defined.

The range of polynomials with odd degree is all the real numbers.

Hence, the domain is

-\infty \:

i.e.

\mathrm{Range\:of\:}-5x-1:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

5 0
3 years ago
If f(x) = −4x 2 + 15, then f(−3)
xxTIMURxx [149]

Answer:

-21

Step-by-step explanation:

f(-3) = -4(-3)² + 15 = -4(9) + 15 = -36 + 15 = -21

8 0
3 years ago
Read 2 more answers
Write a quadratic function in vertex form whose graph has the vertex (-3,5) and passes through the point (0,-14)
dsp73

Answer:

f(x) = -19/9(x + 3)² + 5

Step-by-step explanation:

Given the vertex, (-3, 5) and the point, (0, 14):

Use the following quadratic equation formula in vertex form:

f(x) = a(x - h)² + k

where:

(h, k) = vertex

a = determines whether the graph opens up or down, and makes the graph wide or narrow.

<em>h</em><em> </em>= determines how far left or right the parent function is translated.

<em>k</em> =  determines how far up or down the parent function is translated.

Plug in the values of the vertex, (-3, 5) and the given point, (0, 14) to solve for <em>a</em>:

f(x) = a(x - h)² + k

14 = a(0 + 3)² + 5

14 = a(3)² + 5

14 = a(9) + 5

Subtract 5 from both sides:

-14 - 5 = 9a

-19 = 9a

Divide both sides by 9 to solve for a:

-19/9 = 9a/9

-19/9 = a

Therefore, the quadratic function in vertex form is:

f(x) = -19/9(x + 3)² + 5

Please mark my answers as the Brainliest, if you find this helpful :)

5 0
2 years ago
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