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photoshop1234 [79]
3 years ago
12

11. If 9m - 3 = -318, then 14m = ? a. -28 b. -504 c. -329 d. -584 e. -490

Mathematics
2 answers:
Lisa [10]3 years ago
4 0

Answer:

e. -490

Step-by-step explanation:

-318+3= -315

-315/9= -35

So that would mean m= -35

-35*14= -490

ziro4ka [17]3 years ago
4 0
9m - 3 = -318
+ 3. + 3
9m. = -315
9m / 9 = -315/9
m = -35

14m =
14 (-35) = -490

The answer is e
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Simplify x+2/x^2+2x-3 divide by x+2/x^2-x
ira [324]

\dfrac{\frac{x+2}{x^2+2x-3}}{\frac{x+2}{x^2-x}}

If x\neq-2, then we can immediately cancel the factors of x+2:

\dfrac{\frac1{x^2+2x-3}}{\frac1{x^2-x}}=\dfrac{x^2-x}{x^2+2x-3}

Factorize the numerator and denominator:

x^2-x=x(x-1)

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Next, if x\neq1, then

\dfrac{x^2-x}{x^2+2x-3}=\dfrac{x(x-1)}{(x+3)(x-1)}=\dfrac x{x+3}

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A triangular pyramid has a height of 18 yards and a base with an area of 330 square yards. What is the volume of the pyramid?
WITCHER [35]

Answer:

option C. V=1,980\ yd^{3}

Step-by-step explanation:

we know that

The volume of the triangular pyramid is equal to

V=\frac{1}{3}Bh

where

B is the area of the triangular base

h is the height of the pyramid

In this problem we have

B=330\ yd^{2}

h=18\ yd

substitute in the formula

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3 0
3 years ago
Given right triangle MNL what is the value of cos(M)?
FromTheMoon [43]

Step 1

<u>Find the length of the side MN</u>

we know that

Applying the Pythagorean Theorem

ML^{2} =NL^{2} +MN^{2}

Solve for MN

MN^{2}=ML^{2} -NL^{2}

in this problem

ML=25\ units\\ NL=15\ units

Substitute in the formula above

MN^{2}=25^{2} -15^{2}

MN^{2}=400

MN=20\ units

Step 2

<u>Find the value of cos (M)</u>

we know that

in the right triangle MNL

cos (M)=\frac{adjacent\ side\ angle\ M}{hypotenuse}

adjacent\ side\ angle\ M=MN=20\ units\\ hypotenuse=ML=25\ units

Substitute

cos (M)=\frac{20}{25}

cos (M)=\frac{4}{5}

cos (M)=0.8

therefore

The answer is

The value of cos(M) is equal to 0.8


6 0
3 years ago
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