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antoniya [11.8K]
3 years ago
10

Todos los triángulos equilateros son iguales cierto o falso ​

Mathematics
2 answers:
Vilka [71]3 years ago
6 0

Answer:

true

Step-by-step explanation:

hope this helped

worty [1.4K]3 years ago
5 0

Answer:

Cierto

Step-by-step explanation:

Los triángulos equiláteros son siempre iguales porque siempre tienen ángulos de 60 grados.

Si esto le ayudó, marque como más inteligente

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What is the 10th term of the geometric sequence 400, 200, 100…?
dusya [7]

1. B

2. A

3. C

4. A

5. B

6. C

7. B

Skip, 8,9,12,13,14

10. A

11. C

4 0
3 years ago
Read 2 more answers
One smartphone plan costs $52 per month for talk and messaging and $8 per gigabyte of data used each month. A second smartphone
nevsk [136]

Answer:

a) 6 gigabytes

b) $100

Step-by-step explanation:

Let c represent the total cost in dollars and d represent the amount of data used in gigabytes.

For the first smartphone

One smartphone plan costs $52 per month for talk and messaging and $8 per gigabyte of data used each month.

Equation =

c = 52 + 8d

For the Second smartphone

A second smartphone plan costs $82 per month for talk and messaging and $3 per gigabyte of data used each month.

Equation =>

c = 82 + 3d

How many gigabytes would have to be used for the plans to cost the same?

We would equate both cost to each other

52 + 8d = 82 + 3d

Collect like terms

8d - 3d = 82 - 52

5d = 30

d = 30/5

d = 6

Therefore,

a) The number of gigabytes for the cost of both Smartphone data plans to be the same = 6 gigabytes.

b) The cost of both plans if 6 gigabytes is used =>

c = 52 + 8d

c = 52 + 8 × 6

c = $100

3 0
3 years ago
Find the exact value of cos (arcsin (five divided by thirteen)).
forsale [732]

Answer:

0.99

Step-by-step explanation:

cos(arcsin(5/30)) = 0.98601 ≈ 0.99

3 0
3 years ago
Read 2 more answers
PLEASE HELP: Simplify the expression. Write your answer as a power. 5^2⋅5^9/5
antoniya [11.8K]

Answer:

9.765625×10^6

Step-by-step explanation:

Simplify the following:

5^2×5^9/5

Hint: | Express 5^2×5^9/5 as a single fraction.

5^2×5^9/5 = (5^2×5^9)/5:

(5^2×5^9)/5

Hint: | For all exponents, a^n/a^m = a^(n - m). Apply this to (5^2×5^9)/5.

Combine powers. (5^2×5^9)/5 = 5^(9 + 2 - 1):

5^(9 + 2 - 1)

Hint: | Evaluate 9 + 2.

9 + 2 = 11:

5^(11 - 1)

Hint: | Subtract 1 from 11.

| 1 | 1

- | | 1

| 1 | 0:

5^10

Hint: | Compute 5^10 by repeated squaring. For example a^7 = a a^6 = a (a^3)^2 = a (a a^2)^2.

5^10 = (5^5)^2 = (5×5^4)^2 = (5 (5^2)^2)^2:

(5 (5^2)^2)^2

Hint: | Evaluate 5^2.

5^2 = 25:

(5×25^2)^2

Hint: | Evaluate 25^2.

| 2 | 5

× | 2 | 5

1 | 2 | 5

5 | 0 | 0

6 | 2 | 5:

(5×625)^2

Hint: | Multiply 5 and 625 together.

5×625 = 3125:

3125^2

Hint: | Evaluate 3125^2.

| | | 3 | 1 | 2 | 5

× | | | 3 | 1 | 2 | 5

| | 1 | 5 | 6 | 2 | 5

| | 6 | 2 | 5 | 0 | 0

| 3 | 1 | 2 | 5 | 0 | 0

9 | 3 | 7 | 5 | 0 | 0 | 0

9 | 7 | 6 | 5 | 6 | 2 | 5:

Answer: | 9765625 = 9.765625×10^6

7 0
2 years ago
Are vertical asymptotes determined by inspecting the numerator of a rational equation
Luden [163]

Hello!


Sadly no, vertical asymptotes are determined by setting the denominator of a rational function to zero and then by solving for x.

3 0
3 years ago
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