The area is 15 14/64 which simplifies to 15 4/14 becuse you multiply width times length
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Assuming that there are N lanes and runners are running in the middle of each lane,
width of each lane = (1/N) [m]turning of first lane = π×(R+(1/N)×(1/2))
turning of second lane = π×(R+((1/N)×(1/2))+(1/N))
you can get the difference in turning lane simply by subtracting turning of first lane from turning of second lane.
If i worked the problem correctly, it should be π×(1/N) meter difference between each lane
you would do 7.8 times 0.5 and would get 3.9. You would add 7.8 and 3.9 and get 11.7 That is your answer
You can plug in the table or graph into the equation or the other way around to check your answer