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Nezavi [6.7K]
4 years ago
8

Sammy and 4 friends went out to lunch together. They all ordered the same thing for lunch. Sammy was the only one who ordered de

ssert, which cost $3.75. The total bill was $27.50 before tax and tip. Sammy paid for his own dessert. How much did each person’s lunch cost?
Mathematics
1 answer:
alexandr1967 [171]4 years ago
7 0

Answer:

$4.75.

Step-by-step explanation:

The total cost without the dessert = 27.50 - 3.75

= $23.75

So the cost of each persond lunch = 23.75 / 5

= $4.75.

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Disney held a breakfast for parents and their children to eat with Mickey mouse. adult tickets cost $17.95 and children's ticket
RUDIKE [14]

Answer:

The number of children attending = 324

The number of adults attending  = 176.

Step-by-step explanation:

Here, the total number of people attending = 500

Let us assume the umber of children attending the breakfast = m

So, the number of adults attending the breakfast = 500 - m

Cost of ticket for each children  = $12.95

So, the cost of m children's tickets = m x ( Cost of 1 children ticket)

=  m x ( $12.95)  = 12.95 m .... (1)

Cost of ticket for each adult  = $17.95

So, the cost of (500 -m)  adults's tickets

= (500 - m) x ( Cost of 1 adult ticket)    = (500 -m) x ( $17.95)  

 = 8,975 - 17.95 m     .... (2)

Now, the total earnings from the total ticket sold = $7355

So, The earning from ( Adult's + children's tickets)  = $7355

⇒  12.95 m  +  8,975 - 17.95 m = $7355

or, - 5 m = 7355 - 8975 =   -1620

or, m = 1620/5 = 324

⇒  m =324

Hence the number of children attending =  m = 324

The number of adults attending = 500 - m = 500 - 324 = 176.

7 0
4 years ago
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