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Andreas93 [3]
3 years ago
12

In what year were graphical user interfaces (GUIs) pioneered? 1969 1974 1991 2001

Computers and Technology
2 answers:
natima [27]3 years ago
7 0
Graphical user interface [GUIs] was pioneered in 1969.
Graphical user interface refers to the use of pointing devices and graphic icons to control a computer. It allows users to interact with the computer hardware 
The development and the refinement of graphical user interface had be ongoing for about fifty years. In the late 1960s, Stanford Research Institute scientists developed the online system, which used a new device called mouse. 
Flura [38]3 years ago
7 0

Answer:

The correct option for the following question will be 1969.

Explanation:

GUI stands for Graphical User Interface, developed by Douglas Engelbart Alan Kay at Xerox PARC and was pioneered in 1969. The type of actions that can be taken by the user represented by the graphical user interface and it interacts with the user when the objects changes color, size or visibility.

The objects like button, cursor and icons included in the GUI, these elements can be enhanced with visual effects or sound. The GUI considered as more user-friendly than MS-DOS (text based) and the UNIX shell (operating system).

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RPA or Robotic Process Automation allows organizations to automate tasks which human beings were doing across any applications and systems. The purpose of RPA is to transfer the execution of the process from humans to robots.

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Kyla, a business analyst uses test scripts while testing an application before it is released to the client. Why do business ana
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D. to create a test environment

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After releasing it will be "production"

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3 years ago
What can a method do with a checked exception? Check the exception or ignore it. Return the exception to the sender or handle it
Serggg [28]

Answer:

Handle the exception in a catch block or throw the exception to the method that called this method.

Explanation:

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The catch statement allows the user to define a block of code to be executed, if an error occurs in the try block.

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8 0
3 years ago
Read 2 more answers
Which expression correctly determines that String s1 comes before String s2 in lexicographical order
Assoli18 [71]

Options :

A.) s1 < s2

B.) s1 <= s2

C.) s1.compareTo(s2) == −1

D.) s2.compareTo(s1) < 0

E.) s1.compareTo(s2) < 0

Answer: E.) s1.compareTo(s2) < 0

Explanation: Lexicographical ordering simply means the arrangement of strings based on the how the alphabets or letters of the strings appear. It could also be explained as the dictionary ordering principle of words based on the arrangement of the alphabets. In making lexicographical comparison between strings, the compareTo () method may be employed using the format below.

If first string = s1 ; second string = s2

To compare s1 with s2, the format is ;

s1.compareTo(s2) ;

If s1 comes first, that is, before s2, the method returns a negative value, that is a value less than 0 '< 0', which is the case in the question above.

If s2 comes first, that is, before s1, the method returns a positive value, that is a value greater than 0 '> 0'.

If both are s1 and s2 are the same, the output will be 0.

8 0
3 years ago
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