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noname [10]
4 years ago
8

FIRST CORRECT ANSWER GETS BRAINLIEST AND 50 POINTS.

Mathematics
2 answers:
Murrr4er [49]4 years ago
6 0

Answer:

see below

Step-by-step explanation:

A.  5^3 * 5^-4 = 1/5

It has value between  0 and 1

B. 3^5 / 3^-6 = 177147

It doesn't have a value between 0 and 1

C. (1/4)^3 * (1/4)^2 = 1 / 1024

It has value between  0 and 1

D. (-7)^5 / (-7)^7 = 1/49

It has value between  0 and 1

AnnyKZ [126]4 years ago
4 0

Answer:

A) 5^3*5^{-4}=5^{3-4}=5^{-1}=\frac{1}{5} (Yes. It has a value between zero and one.)

B) \frac{3^5}{3^{-6}}=3^{5-\left(-6\right)}=3^{5+6}=3^{11}=177147 (No. It does not have a value between zero and one.)

C) \left(\frac{1}{4}\right)^3* \left(\frac{1}{4}\right)^2=\left(\frac{1}{4}\right)^{3+2}=\left(\frac{1}{4}\right)^5=\frac{1^5}{4^5}=\frac{1}{1024}. (Yes. It has a value between zero and one.)

D) \frac{\left(-7\right)^5}{\left(-7\right)^7}=\left(-7\right)^{5-7}=\left(-7\right)^{-2}=\frac{1}{\left(-7\right)^2}=\frac{1}{49} (Yes. It has a value between zero and one.)

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5 points, brainliest, and a 5-star rating.
sergij07 [2.7K]

Answer:

ill put them in order fof what they are from top to bottom

Step-by-step explanation:

5,2 ,1, 3, 4. and it starts from the 78 cents being equal to 5 they are in order.

3 0
3 years ago
Compare and contrast the methods you can use to multiply a whole number and a decimal
Troyanec [42]

Answer:

Answer with explanation

When you look at whole numbers , it begin from Zero and has no end , and  decimal ,which is the set of rational numbers and irrational numbers, which came into consideration after whole numbers.

Whole number =0,1,2,3,4,5,6......

Decimal  number = 0.1,0.25,0.325, 0.002000200002000002,..........

→0 × Any Decimal number =0

→ Any other whole number × A decimal number, gives

    Convert that decimal into equivalent fraction,or if irrational number,write it up to three decimal places, and then multiply numerator with Numerator as denominator will remain unchanged to get the required result or multiply the decimal number with the whole number.

For example

→ Whole number × Terminating Decimal

    5 × 0.25

=5 \times \frac{25}{100}\\\\=\frac{125}{100}\\\\=0.25

→Whole number × A non terminating repeating Decimal

2×0.22222222.......

=2 \times \frac{2}{9}\\\\=\frac{4}{9}

= An rational number, that is non terminating repeating decimal.

→→Whole number × An irrational number (A non terminating non repeating Decimal)

5 × √2=5 ×1.414(written to three decimal places)

=7.07(approx)

So, when there is an irrational number , write that decimal up to three decimal places, and then multiply that whole number by that irrational or decimal number to get the result.

3 0
3 years ago
Read 2 more answers
A triangular pyramid has a base with an area of 21.8 square meters, and lateral faces with bases of 7.1 meters and heights of 9
Ymorist [56]

Answer:

Step-by-step explanation:

A triangular pyramid has a base with an area of 21.8 square meters, and lateral faces with bases of 7.1 meters and heights of 9 meters. Enter an expression that can be used to find the surface area of the triangular pyramid.

The expression is written as:

Surface Area = Area of the base + 1/2( Perimeter × Slant height)

8 0
3 years ago
Activity
Sergio039 [100]

Answer:

A:

Dylan’s weight is d.

Twice Dylan’s weight is 2d.

Three pounds more than twice Dylan’s weight is 2d + 3.

So, the expression for Alan’s weight in terms of Dylan’s weight is 2d + 3.

B:

Dylan’s weight is d.

Three times Dylan’s weight is 3d.

Twelve less than three times Dylan’s weight is 3d − 12.

So, the expression for Bruce’s weight in terms of Dylan’s weight is 3d − 12.

C:

Cecil’s weight is the sum of Alan's weight and Bruce's weight.

Alan’s weight in terms of Dylan's weight is 2d + 3.

Bruce’s weight in terms of Dylan's weight is 3d − 12.

So, the expression for Cecil’s weight in terms of Dylan’s weight is (2d + 3) + (3d − 12).

D:

Cecil's weight is (2d + 3) + (3d − 12).

Find Cecil's weight by substituting Dylan’s weight (d = 45) into the expression above:

(2 × 45 + 3) + (3 × 45 − 12)

=  (90 + 3) + (135 − 12)

=  93 + 123

=  216.

If Dylan weighs 45 pounds, then Cecil weighs 216 pounds.

E:

Yes, the expression can be simplified by using the Associative and Commutative Properties of addition and by combining the like terms in the expression.

F:

(2d + 3) + (3d − 12)

First remove the parentheses:

2d + 3 + 3d − 12.

Then group the like terms:

2d + 3d + 3 − 12.

Finally, add and subtract the like terms:

5d − 9.

The expression (2d + 3) + (3d − 12) simplifies to 5d − 9.

G:

Cecil’s weight in terms of Dylan’s weight is 5d – 9.

Find Cecil’s weight by substituting Dylan’s weight (d = 45) into the expression above:

(5 × 45) − 9

= 225 − 9

= 216.

If Dylan weighs 45 pounds, then Cecil weighs 216 pounds.

H:

Yes, the answers are the same. The expression from part D is equivalent to the expression from part G.

I:

Bruce's weight in terms of Dylan’s weight is 3d − 12.

Alan's weight in terms of Dylan’s weight is 2d + 3.

So, the expression (3d − 12) − (2d + 3) represents how much more Bruce weighs than Alan.

J:

The expression is (3d − 12) − (2d + 3).

Evaluate the expression by substituting Dylan’s weight (d = 45) into it:

(3 × 45 − 12) − (2 × 45 + 3)

= (135 − 12) − (90 + 3)

= (123) − (93)

= 30.

Bruce weighs 30 pounds more than Alan weighs.

K:

The expression (3d − 12) − (2d + 3) simplifies to d − 15.

L:

The expression is d − 15.

Evaluate the expression by substituting Dylan’s weight (d = 45) into it:

45 − 15 = 30.

Bruce weighs 30 pounds more than Alan. This is the same answer as in part J.

Do not copy, it's the exact answer from edmuentum

5 0
3 years ago
Which of the following illustrates the truth value of the given conditional statement if 6*3=18, then 4+8=20
denis-greek [22]
Conditional statement represents two statements, the "p" and the "q". Where p is the hypothesis and q is the conclusion.

The table of conditional statement:
(p)     (q)     (p -> q)
 T       T          T
 T       F          F
 F       T          T
 F       F          F

As shown on the table, (p -> q) can only be false if the "p statement" is true while the "q statement" is false.

The given states that, "If 6*3 = 18, then 8+4 = 20", 
set p: 6*3 = 18
      q: 8+4 = 20

Since p is true and q is false, then the truth value (p->q) is false.
7 0
3 years ago
Read 2 more answers
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