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noname [10]
3 years ago
8

FIRST CORRECT ANSWER GETS BRAINLIEST AND 50 POINTS.

Mathematics
2 answers:
Murrr4er [49]3 years ago
6 0

Answer:

see below

Step-by-step explanation:

A.  5^3 * 5^-4 = 1/5

It has value between  0 and 1

B. 3^5 / 3^-6 = 177147

It doesn't have a value between 0 and 1

C. (1/4)^3 * (1/4)^2 = 1 / 1024

It has value between  0 and 1

D. (-7)^5 / (-7)^7 = 1/49

It has value between  0 and 1

AnnyKZ [126]3 years ago
4 0

Answer:

A) 5^3*5^{-4}=5^{3-4}=5^{-1}=\frac{1}{5} (Yes. It has a value between zero and one.)

B) \frac{3^5}{3^{-6}}=3^{5-\left(-6\right)}=3^{5+6}=3^{11}=177147 (No. It does not have a value between zero and one.)

C) \left(\frac{1}{4}\right)^3* \left(\frac{1}{4}\right)^2=\left(\frac{1}{4}\right)^{3+2}=\left(\frac{1}{4}\right)^5=\frac{1^5}{4^5}=\frac{1}{1024}. (Yes. It has a value between zero and one.)

D) \frac{\left(-7\right)^5}{\left(-7\right)^7}=\left(-7\right)^{5-7}=\left(-7\right)^{-2}=\frac{1}{\left(-7\right)^2}=\frac{1}{49} (Yes. It has a value between zero and one.)

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The two non negative real numbers with a sum of 64 that have the largest possible​ product are; 32 and 32.

<h3>How do we solve the nonnegative real numbers?</h3>

Let the two numbers be x and y.

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