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MrRa [10]
3 years ago
5

15. Explain why we need to specify 0 < b < 1 and b > 1 as valid values for the base b in the expression logb(xx).

Mathematics
1 answer:
damaskus [11]3 years ago
3 0

Answer:

The base (b) has to be positive and different of 1. The logarithm is the inverse of exponential, so:

logb(a) = x ⇒ a = bˣ

So, for b = 0 ⇒ 0ˣ = a

And there is impossible, "a" only could be 0.

For b = 1 ⇒ 1ˣ = a

And the same thing would happen, the logarithming would be to be 1, and the function will be extremally restricted.

For b<0, then the expression a = bˣ will be also restricted, and will not represent all values of a.

So, 0<b<1 and b >1.

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For a project, Gabrielle made a model of an Egyptian pyramid. The square base has a side length measuring 10 inches. The pyramid
Varvara68 [4.7K]
The pyramid is shown in the diagram below.
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We have the side of the square, so the area is = 10×10 = 100

We need the height of the triangle to work out its area. We can find out by using the height of the pyramid and half of the length of the side of the square.

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3 0
3 years ago
Read 2 more answers
Find the 59th term of the arithmetic sequence <br> 29,37,45,...
liberstina [14]

Answer:

13,456

Step-by-step explanation:

Tn= a+(n-1)d

a is the first term, n is the given number and d is the common difference. d is given by subtracting the first term from the second term or the second from the third. Therefore the the 59th term of the sequence 29, 37, 45 is,

Tn= 29+(59-1)8

=29(58)8

=13,456

4 0
3 years ago
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