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MrRa [10]
3 years ago
5

15. Explain why we need to specify 0 < b < 1 and b > 1 as valid values for the base b in the expression logb(xx).

Mathematics
1 answer:
damaskus [11]3 years ago
3 0

Answer:

The base (b) has to be positive and different of 1. The logarithm is the inverse of exponential, so:

logb(a) = x ⇒ a = bˣ

So, for b = 0 ⇒ 0ˣ = a

And there is impossible, "a" only could be 0.

For b = 1 ⇒ 1ˣ = a

And the same thing would happen, the logarithming would be to be 1, and the function will be extremally restricted.

For b<0, then the expression a = bˣ will be also restricted, and will not represent all values of a.

So, 0<b<1 and b >1.

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<u>The correct answer</u> is:
4.

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Read 2 more answers
Suppose IQ scores were obtained for 20 randomly selected sets of couples. The 20 pairs of measurements yield x overbarequals100.
LenaWriter [7]

Answer:

\hat y = -3.34+ 1.07(91) = 94.03

Step-by-step explanation:

Data given

n=20 represent the sampel size

\bar X = 100.39 represent the sample mean for the independent variable (IQ score of the husband)

\bar y = 103.6 represent the sample mean for the dependent variable.

r =0.925 represent the correlation coefficient

Solution to the problem

The general expression for a linear model is given by:

y = \beta_0 + \beta_1 x

Where \beta_0 is the intercept and \beta_1 the slope

For this case we have a linear model given by the following expression:

\hat y = -3.34 +1.07 x

Where -3.34 is the intercept and 1.07 the slope. In order to find the best predicted value when X = 91 we just need to replace into the equation the value of 91 and we got this:

\hat y = -3.34+ 1.07(91) = 94.03

On this case is the best predicted value because E(\hat y) = y we have an unbiased estimator.

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