Answer:
d 20.4 years
Step-by-step explanation:
The equation is
A = Pe ^(rt)
We know that r = .034
We want the money to double so A = 2P
Substitute in
2P = P e ^(.034t)
Divide by P
2P/P = P/P e ^(.034t)
2 = e^ (.034t)
Take the natural log on each side
ln (2) = ln(e^ (.034t))
ln (2) = .034t
Divide by .034
ln (2) /.034 = .034t/.034
ln (2)/.034 = t
20.3867 =t
The answer is p x q to the 9th power or the first answer.
The Domain is the first number of the pair
D= -7, -6, -5, -4
The Range is the second number of the pair
R= 5, 1, 0, when a number repeats like the number one you can put it once.
Answer:
73*-2 =-146 you have to multiply the 73 to the -2
Step-by-step explanation:
<em>4℉.</em>
What we know about Degrees is that there is a<em> </em><u><em>Positive</em></u> type and a <u><em>negative</em></u> type.
(i.e: 30℉ is <u><em>positive</em></u> and -30℉ is <u><em>negative</em></u>.)
If the temperature was -4℉ at 7AM, then it is negative. If it goes up by an amount that is more than 4 then that negative will go up to a positive temperature. In this case: At 9AM it was 8° <u><em>warmer</em></u>.
<u><em>Warmer</em></u><em> is a </em><u><em>keyword</em></u><u>.</u> If it is warmer by an amount, Negative temperatures <u><em>will go up to a positive</em></u> and positive temperature <u><em>will just go up</em></u>. If it gets cooler, negative temperatures <u><em>will go down further</em></u> and positive temperatures <u><em>will go down to a negative</em></u>.
So lets work out this problem with our newfound knowledge.
-4° F at 7AM
8° warmer at 9AM
-4 + 8 = 4.
<em>The temperature was 4° at 9AM.</em>
-Snooky
