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lara [203]
2 years ago
12

A shirt that originally costs $35.99 is on sale for 60% off. What is the sale price of the shirt? Screen reader support enabled.

Mathematics
2 answers:
Jlenok [28]2 years ago
7 0

Answer:

14.40

Step-by-step explanation:

The sale price of the shirt is around $14.40 I think

sineoko [7]2 years ago
3 0

Solution:

<u>Note that:</u>

  • 35.99 - (35.99 x 60/100) = Sale Price

<u>Simplify the equation to obtain the sale price.</u>

  • 35.99 - (35.99 x 60/100) = Sale Price
  • => 35.99 - (35.99 x 6/10) = Sale Price
  • => 35.99 - (107.97/5) = Sale Price
  • => 35.990 - 21.594 = Sale Price
  • => $14.396 = Sale Price
  • => $14.40 (Rounded)
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Answer:    3/5

Step-by-step explanation:

Fist find  out how many whites are there and divide it by the total to find the probability.

9/15   simplify it to  3/5

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2 years ago
Need help on this one please answer asap
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3 years ago
The heights of a random sample of 50 college students showed a mean of 174.5 centimeters and a standard deviation of 6.9 centime
Minchanka [31]

Answer:

Step-by-step explanation:

Hello!

For me, the first step to any statistics exercise is to determine what is the variable of interest and it's distribution.

In this example the variable is:

X: height of a college student. (cm)

There is no information about the variable distribution. To estimate the population mean you need a variable with at least a normal distribution since the mean is a parameter of it.

The option you have is to apply the Central Limit Theorem.

The central limit theorem states that if you have a population with probability function f(X;μ,δ²) from which a random sample of size n is selected. Then the distribution of the sample mean tends to the normal distribution with mean μ and variance δ²/n when the sample size tends to infinity.

As a rule, a sample of size greater than or equal to 30 is considered sufficient to apply the theorem and use the approximation.

The sample size in this exercise is n=50 so we can apply the theorem and approximate the distribution of the sample mean to normal:

X[bar]~~N(μ;σ2/n)

Thanks to this approximation you can use an approximation of the standard normal to calculate the confidence interval:

98% CI

1 - α: 0.98

⇒α: 0.02

α/2: 0.01

Z_{1-\alpha /2}= Z_{1-0.01}= Z_{0.99} =2.334

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

174.5 ± 2.334* \frac{6.9}{\sqrt{50} }

[172.22; 176.78]

With a confidence level of 98%, you'd expect that the true average height of college students will be contained in the interval [172.22; 176.78].

I hope it helps!

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3 years ago
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Step-by-step explanation:

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3 years ago
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Ilya [14]

Answer:

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Step-by-step explanation:

10+20 equal 30

4 0
3 years ago
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