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Dmitry [639]
3 years ago
9

Write the equation of a line in slope-intercept form that is perpendicular to the line y = 3/5 = 1 and passes through the point

(-9, 4).
Mathematics
1 answer:
4vir4ik [10]3 years ago
4 0

The slope of the line y=\frac{3}{5} x-1 is m=\frac{3}{5}.

The line perpendicular to the above line has slope -\frac{1}{m} =-\frac{5}{3}

Its equation is y=-\frac{5}{3} x+c. Since this line passes through, (-9,4),

4=-\frac{5}{3} )(-9)+c\\ c=-11

Thus the equation of the line in slope intercept form is y=-\frac{5}{3} x-11

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Hey there!

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