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4 years ago

What is x2+5x=0? Please show all work!

Mathematics

2 answers:

Alexxandr [17]4 years ago

7 0

X2+5x=0
7x+0
divide both sides by 7
7 divided by 0 is 0
x=0
0=0

navik [9.2K]4 years ago

4 0

1 Factor out the common term x

x(x+5)=0

2 Solve for x

x=0,-5

I hope this helps. :)

Have a great day.

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What is the greatest common factor of 44c^5, 22c^3 and 11c^4

Alexxandr [17]

$\text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3$

Solution:

Given that, we have to find the greatest common factor of $44c^5, 22c^3 , 11c^4$

The greatest number that is a factor of two (or more) other numbers.

When we find all the factors of two or more numbers, and some factors are the same ("common"), then the largest of those common factors is the Greatest Common Factor

$\underline{\text{ GCF of } 44c^5, 22c^3 , 11c^4 :}$

First find the GCF of numbers and then find the GCF of variables and then multiply them together

Step 1: GCF of 44, 22 and 11

The factors of 11 are: 1, 11

The factors of 22 are: 1, 2, 11, 22

The factors of 44 are: 1, 2, 4, 11, 22, 44

11 is the greatest factor that is common in above three list

Then the greatest common factor is 11

$\text{ Step 2: GCF of }c^5, c^3 , c^4$

$c^5 = c^3 \times c^2\\\\c^3 = c^2 \times c^1 \text{ or } c^3\\\\c^4 = c^3 \times c^1$

Thus the greatest common factor is $c^3$

Step 3: Multiply the GCF of 44, 22, 11 and GCF of $c^5, c^3 , c^4$

$\text{ GCF of } 44c^5, 22c^3 , 11c^4 = 11 \times c^3 = 11c^3$

Thus $\text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3$

8 0

3 years ago

All of the following are equivalent, except _____.

puteri [66]

Everything except 11x2

3 0

3 years ago

Read 2 more answers

What is the product of 1.7 × 10−13 and 3.5 × 1025? 1.8 × 1012 2.06 × 1012 3.5 × 1012 5.95 × 1012

Anuta_ua [19.1K]

Do you have paper and a pen on you this is very simple to workout The first one is 4 and the other one is 3587.5 and the last one is 8.0992869

3 0

3 years ago

John sells hamburgers ($3) and cheeseburgers ($3.50). One afternoon he sells a total of 24 burger for $79. How many of these wer

ankoles [38]

John sold 10 hamburgers and 14 cheeseburgers.

Step-by-step explanation:

Given,

Cost of one hamburger = $3

Cost of one cheeseburger = $3.50

Total burgers sold = 24

Total revenue earned = $79

Let,

Number of hamburgers sold = x

Number of cheeseburgers sold = y

According to given statement;

x+y=24 Eqn 1

3x+3.50y=79 Eqn 2

Multiplying Eqn 1 by 3

$3(x+y=24)\\3x+3y=72\ \ \ Eqn\ 3$

Subtracting Eqn 3 from Eqn 2

$(3x+3.50y)-(3x+3y)=79-72\\3x+3.50y-3x-3y=7\\0.50y=7$

Dividing both sides by 0.50

$\frac{0.50y}{0.50}=\frac{7}{0.50}\\y=14$

Putting y=14 in Eqn 1

$x+14=24\\x=24-14\\x=10$

John sold 10 hamburgers and 14 cheeseburgers.

Keywords: linear equation, elimination method

Learn more about elimination method at:

#LearnwithBrainly

3 0

3 years ago

I need help with this problem

mixer [17]

It is D i hopes this helped like plz

8 0

3 years ago