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Neporo4naja [7]
3 years ago
11

9 students volunteer for a committee. How many different 7-person committees can be chosen? 1 181,440 362,880 36

Mathematics
2 answers:
Misha Larkins [42]3 years ago
8 0

Answer:

The correct answer is D. 36

Step-by-step explanation:

Number of students volunteer available for the committee = 9

Capacity of the committee which is to be formed = 7

So, We need to select a committee of 7 peoples

Thus, we need to find the total number of different ways in which 7 peoples can be selected from the total number of 9 peoples.

\text{Number of different 7-persons committee which can be chosen = }_7^9\txterm{C}\\\\\text{Number of different 7-persons committee which can be chosen = } \frac{9!}{7!\times 2!}\\\\\text{Number of different 7-persons committee which can be chosen = }\frac{9\times 8}{2}\\\\\text{Number of different 7-persons committee which can be chosen = }36

Therefore, The correct answer is D. 36

Mama L [17]3 years ago
6 0
Its 36. use the type A!/B!(A-B)! 
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timofeeve [1]
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P max ( 6 , 5 ) = 27
3 0
3 years ago
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3 years ago
The explicit rule for the arithmetic sequence shown in the graph is a↓n=9.5+2(n-1)
Virty [35]

Answer:

True.

Step-by-step explanation:

The explicit form for an arithmetic sequence is:

a_n=a_1+d(n-1)

where a_1 is the first term and d is the common difference.

The common difference here is 2 because the y's are going up by 2 while the x's are going up by 1.

Yes, the common difference is the slope.

So we have d=2.

The first term is 9.5 because that is what happens when x=1.

x is n.

y is a_n.

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----

You can also verify by plugging in numbers for n and see if you get the outputs mentioned in the pairs given:

Let n=1:

a_1=9.5+2(1-1)

a_1=9.5+2(0)

a_1=9.5+0

a_1=9.5

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a_2=9.5+2(2-1)

a_2=9.5+2(1)

a_2=9.5+2

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a_3=9.5+4

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Let n=4:

a_4=9.5+2(4-1)

a_4=9.5+2(3)

a_4=9.5+6

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Let n=5:

a_5=9.5+2(5-1)

a_5=9.5+2(4)

a_5=9.5+8

a_5=17.5

Let n=6:

a_6=9.5+2(6-1)

a_6=9.5+2(5)

a_6=9.5+10

a_6=19.5

We have confirmed that we get all 6 of the mentioned points using the equation they gave.

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7nadin3 [17]
Hey there!!

Okay so here are the steps....

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<u>

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enot [183]
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