9 students volunteer for a committee. How many different 7-person committees can be chosen? 1 181,440 362,880 36

Mathematics

2 answers:

Misha Larkins [42]2 years ago

8 0

Answer:

The correct answer is D. 36

Step-by-step explanation:

Number of students volunteer available for the committee = 9

Capacity of the committee which is to be formed = 7

So, We need to select a committee of 7 peoples

Thus, we need to find the total number of different ways in which 7 peoples can be selected from the total number of 9 peoples.

$\text{Number of different 7-persons committee which can be chosen = }_7^9\txterm{C}\\\\\text{Number of different 7-persons committee which can be chosen = } \frac{9!}{7!\times 2!}\\\\\text{Number of different 7-persons committee which can be chosen = }\frac{9\times 8}{2}\\\\\text{Number of different 7-persons committee which can be chosen = }36$

Therefore, The correct answer is D. 36

Mama L [17]2 years ago

6 0

Its 36. use the type A!/B!(A-B)!

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Kelly was asked to determine whether △KLN is congruent to △MNL. She noted that KL ≅ MN, LM ≅ KN, and that the three pairs of cor

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Answer:

<h2>Kelly is wrong, with this congruent parts, we can conclude that triangles are congruent.</h2>

Step-by-step explanation:

To demonstrate congruent triangles, we need to use the proper postulates. There are at least 5 postulates we can use.

Angle-Angle-Side Theorem (AAS theorem).
Hypotenuse-Leg Theorem (HL theorem).
Side-Side-Side Postulate (SSS postulate).
Angle-Side-Angle Postulate (ASA postulate).
Side-Angle-Side Postulate (SAS postulate).

In this case, Kelly SAS postulate, because the corresponding sides-angles-sides are congruent, i.e., KL ≅ MN and LM ≅ KN, also, all corresponding angles are congruent.

So, as you can see, only using SAS postulate, the congruency can be demonstrated. (Refer to the image attached to see an example of SAS postulate)