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2 years ago

What is the value of x in the figure below in this diagram abd cad.

Mathematics

2 answers:

Alekssandra [29.7K]2 years ago

5 0

Answer:

Option C.

Step-by-step explanation:

Given information: $\triangle ABD\sim \triangle CAD$ , AB=12, BD=x, BC=27.

In triangle ABC and triangle DBA,

$\angle BAC=\angle BDA=90^{\circ}$

$\angle ABC=\angle DBA$ (Reflexive property)

By AA property of similarity triangle ABC and triangle DBA are similar.

The corresponding parts of similar triangles are proportional.

$\dfrac{AB}{CB}=\dfrac{BD}{BA}$

$\dfrac{12}{27}=\dfrac{x}{12}$

Multiply both sides by 12.

$\dfrac{12}{27}\times 12=\dfrac{x}{12}\times 12$

$\dfrac{144}{27}=x$

$\dfrac{16}{3}=x$

Therefore, the correct option is C.

Annette [7]2 years ago

4 0

Answer: C. - 16/3

Step-by-step explanation:

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Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the proporti

hodyreva [135]

Answer:

The sample size n = 4225

Step-by-step explanation:

We will use maximum error formula = $\frac{z_{a} S.D}{\sqrt{n} }$

but we will find sample size "n"

$\sqrt{n} = \frac{z_{a} S.D}{maximum error}$

Squaring on both sides , we get

$n = (\frac{z_{a} S.D}{maximum error})^2$

Given 99% confidence interval (z value) = 2.56

given maximum error = 0.02

$n = (\frac{z_{a} p(1-p)}{maximum error})^2$

n≤ $(\frac{2.56X\frac{1}{2} }{0.02}) ^{2}$ ( here S.D = p(1-p) ≤ 1/2

on simplification , we get n = 4225

Conclusion:

The sample size of two samples is n = 4225

verification:-

We will use maximum error formula = $\frac{z_{a} S.D}{\sqrt{n} }$ = $\frac{2.56 1/2}{\ \sqrt{4225} }$ = 0.0196

substitute all values and simplify we get maximum error is 0.02

4 0

3 years ago

find an equation of the tangent line to the curve at the given point. y=sqrt(x) (1,1) Ive never been good with these equations a

Nady [450]

Equation of a tangent line of a curve is:
y- y0 = f´ (x0) (x - x0 ). In this case: x0=1, y0=1
f´(x)= $\frac{1}{2 \sqrt{x} }$ (Derivation)
f´(x0)= $\frac{1}{2}$
y - 1 = 1/2 ( x - 1 )
y - 1 = 1/2 x - 1/2
y = 1/2 x - 1/2 + 1
y = $\frac{1}{2}x+ \frac{1}{2}$