3 years ago

What is the area of ΔABC? Round to the nearest tenth of a square unit.

Mathematics

2 answers:

saveliy_v [14]3 years ago

5 0

Answer:

Step-by-step explanation:

Westkost [7]3 years ago

3 0

Draw a perpendicular segment from point C to the midpoint of AB. Using the trig sine function sin 80 = x/6 which gives 5.91 for the perpendicular segment. Using the formula A=1/2bh, A= 1/2 x5.91x2sqrt 2 A= 8.4

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Simplify sin^2y/sec^2 y−1 to a single trigonometric function

liubo4ka [24]

Answer:

$\frac{ { \sin}^{2} y}{ { \sec}^{2}y - 1 } = { \cos }^{2} y$

Step-by-step explanation:

We know that ${ \tan }^{2} y = { \sec }^{2} y - 1$

Also , ${ \tan}^{2} y = \frac{ { \sin }^{2} y}{ { \cos }^{2}y }$

So ,

$\frac{ { \sin }^{2}y }{ { \sec }^{2}y - 1 } = \frac{ { \sin}^{2} y}{ { \tan }^{2} y} = \frac{ { \sin }^{2}y }{ \frac{ { \sin}^{2} y}{ { \cos}^{2}y } } = { \cos }^{2} y$