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3 years ago

14

Calculate the force of gravity on earth of an object that has a mass of 200 kg.

1 answer:

ElenaW [278]3 years ago

7 0

Gravity= 9.8 × 200 =1960N

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Write your answer in scientific notation. (3.2 x 10^-2) + (3.2 x 10^-4) + (2.8 x 10^-2)

mars1129 [50]

3.2 x 10^-2 + 3.2 x 10^-4 + 2.8 x 10^-2
= 3.2 + 2.8
= 6 x 10^-2 + 3.2 x 10^-4
Convert 3.2 into fraction which is 16/5
And express with a positive exponent using “a^-n = 1/a^n” therefore
= 6 x 10^-2 + 16/5 x 1/10^4
= 6 x 1/10^2 + 16/5 x 10^4
= 6 x 1/100 + 16/5 x 10,000
Reduce 6 and 100 with the GCF ‘2’
Then reduce 16 and 10,000 with 16
= 3 x 1/50 + 1/5 x 625
Multiply
= 3/50 + 1/3125
Then add
The answer is
= 377/6250
= 0.06032

3 0

3 years ago

On Monday joe bought 10 cups of coffee and 5 doughnuts for his office at the cost of $16.50. On Tuesday he bought 5 cups of coff

svp [43]

Answer:

each cup cost 1.25 on Tuesday

4 0

4 years ago

Can anybody help me???

Tasya [4]

#10

$\\ \rm\longmapsto 0$

#11

Last three i.e Option B,C,D

#13

It started from negative ends at positive hence

$\\ \rm\longmapsto y=-|x|+2$

#14

(-3,-10)

$\\ \rm\longmapsto 2(-3)-(-10)=4$

$\\ \rm\longmapsto -6+10=4$

Proved

#15

(1,1)

$\\ \rm\longmapsto 1=(1-2)^2=(-1)^2=1$

#16

(2,-4)

$\\ \rm\longmapsto -2-2(-4)>3$

$\\ \rm\longmapsto -2+8>3$

$\\ \rm\longmapsto 6>3$

5 0

3 years ago

A triangle has an area of 240 square Inches. The height of the triangle is 15 inches. What is the length of the base of the tria

Alenkinab [10]

Answer:

$32\:\mathrm{in}$

Step-by-step explanation:

The area of a triangle is given by $A=\frac{1}{2}\cdot b\cdot h$ .

Substituting given values, we have:

$240=\frac{1}{2}\cdot b\cdot 15,\\480=15b,\\b=\frac{480}{15}=\boxed{32\:\mathrm{in}}$

7 0

3 years ago

Read 2 more answers

nadya68 [22]

Answer:

1) yes

2) No

3) No

4) yes

5) No

Step-by-step explanation:

1) f(0)=0, f(1)=1, f(2)=2, f(3)=3, then $f[\{0, 1, 2, 3\}]=\{0, 1, 2, 3\}$

2) f(0)=0, $1^2=1\equiv 1 \text{mod 4}$ , then f(1)=1; $2^2=4\equiv 0 \text{ mod 4}$ , then f(2)=0; $3^2=9\equiv 1 \text{mod 4}$ , then f(3)=1

Then $f[\{0, 1, 2, 3\}]=\{0, 1, 3\}$ , this means that f isn't onto.

3.

f(0)=0;

$1^1-1=0$ , then f(1)=0
$2^2-2=2$ , then f(2)=2
$3^2-3=6\equiv 2 \text{ mod 4}$ , then f(3)=2

Then $f[\{0, 1, 2, 3\}]=\{0, 2\}$ , this means that f isn't onto.

4. $f[\{0, 1, 2, 3\}]=\{0, 1, 2,3\}$ , then f is onto.

5. $f[\{0, 1, 2, 3\}]=\{1, 2\}$ , this means that f isn't onto.

6 0

3 years ago