Someone help me please!!

What other information must be given in order to be able to prove the two triangles congruent by AAS

Oksana_A [137]

Either the second or third. I think the third since the second can be proven with the given info, and then you just need to know another angle from each triangle is congruent. also, its worth knowing that it is also possible to prove similar triangles with just angle angle, since that would automatically make the last angles equal.

5 0

4 years ago

PLEASE HELP ME I WILL GIVE BRAINLIEST!! 9 PLEASSSEEEE

olga2289 [7]

Answer:

$\frac{2}{9}$

Step-by-step explanation:

there is a four out of nine change to get a green marble

there is a 1/2 change to get heads

$\frac{4}{9}$ × $\frac{1}{2} =\frac{2}{9}$

5 0

4 years ago

What is the opposite of the opposite of negative nine?

pogonyaev

Answer:

-9 or negative 9

Step-by-step explanation:

The opposite of negative 9 is positive 9.

The opposite of <em>that</em> is negative 9.

8 0

3 years ago

Read 2 more answers

A right triangle has legs of 5 ft and 6 ft. What is the length of the hypotenuse? _____ ft. A. 7.8 B. 3.3 C. 11.0 D. 1.0

Delicious77 [7]

Answer:

Option A is the correct option.

Step-by-step explanation:

Base (b) = 5 ft

Perpendicular (P) = 6 ft

Hypotenuse (h) = ?

Now,

Using Pythagoras theorem,

${h}^{2} = {p}^{2} + {b}^{2}$

${h}^{2} = {(6)}^{2} + {(5)}^{2}$

${h}^{2} = 36 + 25$

${h}^{2} = 61$

$h = \sqrt{61}$

$h = 7.8 \: ft$

Hope this helps...

Good luck on your assignment

8 0

3 years ago

Which of the following is not a solution to the system of linear equations below?

ra1l [238]

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}5y=3x+15&\text{subtract 3x from both sides}\\6x=10y-30&\text{subtract 10y from both sides}\end{array}\right\\\left\{\begin{array}{ccc}-3x+5y=15\\6x-10y=-30&\text{divide both sides by 2}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}-3x+5y=15\\3x-5y=-15\end{array}\right}\\.\qquad0=0\qquad\bold{TRUE}\\\\\bold{Infinitely\ many\ solutions}\\\\5y=3x+15\qquad\text{divide both sides by 5}\\\\y=\dfrac{3}{5}x+3\qquad(*)\\\\\text{Put the coordinates of the points to the equation (*)}$

$A.\ (5,\ 6)\\\\6=\dfrac{3}{5}(5)+3\\\\6=3+3\\\\6=6\qquad\bold{CORRECT}\\\\B.\ (-15,\ 12)\\\\12=\dfrac{3}{5}(-15)+3\\\\12=(3)(-3)+3\\\\12=-9+3\\\\12=-6\qquad\bold{FALSE}\\\\C.\ (0,\ 3)\\\\3=\dfrac{3}{5}(0)+3\\\\3=0+3\\\\3=3\qquad\bold{CORRECT}\\\\D.\ (-10,\ -3)\\\\-3=\dfrac{3}{5}(-10)+3\\\\-3=(3)(-2)+3\\\\-3=-6+3\\\\-3=-3\qquad\bold{CORRECT}$

5 0

4 years ago