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ratelena [41]
4 years ago
9

To get from one town to another, Jack must travel 7 miles east and 24 miles south. What is the direct distance between the two t

owns? 31 miles 17 miles 25 miles 15 miles
Mathematics
1 answer:
Step2247 [10]4 years ago
3 0
The 7 miles and 24 miles make up two "legs" of a right triangle.
The third side (or hypotenuse) is the distance between the towns.
distance^2 = 7^2 + 24^2
distance^2 = 49 + 576
distance^2 = 625
distance = square root of 625 or 25
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lawyer [7]
2x -20 -1 =0
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4 0
2 years ago
4x-y=10 as coordinates with the y as -6
IgorC [24]

Answer:

(1,-6)

Step-by-step explanation:

4x - y = 10

4x -(-6) = 10

4x + 6 = 10

    - 6    - 6

4x = 4

/4    /4

x = 1

(x, y) -> (1,-6)

Check your answer:

4x - y = 10

4(1) - (-6) = 10

4 + 6 = 10

10 = 10

This statement is correct

Hope this helps!

6 0
2 years ago
Read 2 more answers
Could ΔABC be congruent to ΔADC by SSS? Explain. Yes, but only if AB ≅ DC. Yes, but only if BC ≅ DC. No, because AB is not congr
Sonbull [250]

Answer:

<em>Yes, but only if BC ≅ DC; Option B</em>

Step-by-step explanation:

There are 4 possible ways to determine whether two triangles are congruent, and they are the following ;

ASA ( Angle - Side - Angle ),

SAS ( Side - Angle - Side ),

AAS ( Angle - Angle - Side ), and

SSS ( Side - Side - Side )

It is known here that we must prove these triangles congruence through SSS. A triangle can thus be made possible through the congruence of corresponding sides;

Now if we were to create these triangles it would be that BC and DC are, if the triangles were to coincide with one another, the apparent same length if it were that these two Δs really are ≅. Thus;

<em>Solution; Yes, but only if BC ≅ DC</em>

5 0
3 years ago
Please help me with this question
san4es73 [151]

Step-by-step explanation:

Given: f'(x) = x^2e^{2x^3} and f(0) = 0

We can solve for f(x) by writing

\displaystyle f(x) = \int f'(x)dx=\int x^2e^{2x^3}dx

Let u = 2x^3

\:\:\:\:du=6x^2dx

Then

\displaystyle f(x) = \int x^2e^{2x^3}dx = \dfrac{1}{6}\int e^u du

\displaystyle \:\:\:\:\:\:\:=\frac{1}{6}e^{2x^3} + k

We know that f(0) = 0 so we can find the value for k:

f(0) = \frac{1}{6}(1) + k \Rightarrow k = -\frac{1}{6}

Therefore,

\displaystyle f(x) = \frac{1}{6} \left(e^{2x^3} - 1 \right)

5 0
3 years ago
Reduce improper 24/5
iogann1982 [59]
The answer is 4 4/5
6 0
3 years ago
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