Find the range for f(x) = x^2 1, for x < 0. y ≥ 1 y > 1 y < 1 y ≤ 1
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Answer:
<h2>Check out the image.</h2>Step-by-step explanation:
Let, the equation of the straight line is y = mx + c; where m is the slope of the equation and c is the constant.
The line has the slope 1.
Hence, the equation becomes y = x + c.
Since, the line passes through (-6, -2), -2 = -6 + c or, c = 4.
Hence, the equation of the straight line becomes y = x + 4.
Putting x = 0, we get, y = 4.
The line passes through (0, 4).
