Answer:
The number of key rings sold on a particular day when the total profit is $5,000 is 4,000 rings.
Step-by-step explanation:
The question is incomplete.
<em>An owner of a key rings manufacturing company found that the profit earned (in thousands of dollars) per day by selling n number of key rings is given by </em>
<em />
<em />
<em>where n is the number of key rings in thousands.</em>
<em>Find the number of key rings sold on a particular day when the total profit is $5,000.</em>
<em />
We have the profit defined by a quadratic function.
We have to calculate n, for which the profit is $5,000.
We have to calculate the roots of the polynomial we use the quadratic equation:
n1 is not valid, as the amount of rings sold can not be negative.
Then, the solution is n=4 or 4,000 rings sold.
Use subtitution method to solve the problem.
First, change y to the value of x in order to find the exact value of x.
x + y = 4
y = 4 - x
Second, subtitute y with 4 - x from the first equation
y = -x² + 2x + 4
4 - x = -x² + 2x + 4
move all terms to the left side
x² - 2x - x + 4 - 4 = 0
x² - 3x = 0
x(x - 3) = 0
x = 0 or x = 3
Third, now we have 2 values of x. Find the value of y for each of x
For x = 0
y = 4 - x
y = 4 - 0
y = 4
For x = 3
y = 4 - x
y = 4 - 3
y = 1
The solution is (0,4) and (3,1). The answer is option b
How do linear, quadratic, and exponential functions compare?
Answer:
How can all the solutions to an equation in two variables be represented?
<u><em>The solution to a system of linear equations in two variables is any ordered pair x,y which satisfies each equation independently. U can Graph, solutions are points at which the lines intersect.</em></u>
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<u><em>How can all the solutions to an equation in two variables be represented?</em></u>
<u><em>you can solve it by Iterative method and Newton Raphson's method.</em></u>
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<u><em>How are solutions to a system of nonlinear equations found?
</em></u>
Solve the linear equation for one variable.
Substitute the value of the variable into the nonlinear equation.
Solve the nonlinear equation for the variable.
Substitute the solution(s) into either equation to solve for the other variable.
<u><em>
</em></u>
<u><em>How can solutions to a system of nonlinear equations be approximated? U can find the solutions to a system of nonlinear equations by finding the points of intersection. The points of intersection give us an x value and a y value. Using the example system of nonlinear equations, let's look at how u can find approximate solutions.</em></u>
Answer:
x ≈ 15.9
Step-by-step explanation:
Using Pythagoras' identity in the right triangle
x² + 6² = 17²
x² + 36 = 289 ( subtract 36 from both sides )
x² = 253 ( take the square root of both sides )
x = 
≈ 15.9 ( to the nearest tenth )
