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vekshin1
3 years ago
8

Which number is a prime number 87,51,31,39

Mathematics
1 answer:
Sveta_85 [38]3 years ago
7 0

Answer:

87 is the prime number

Step-by-step explanation:

the only factor of 87 is 1 and 87 which makes it prime



BRAINIEST PLZZZZZZ.


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PRECALCULUS HONORS HELP ME PLZ AND THANKS
Natalka [10]

Inequalities are used to show the relationship between unequal expressions

  • <em>The set notation of (5) and (6) are: </em>\{x : -6 > x \ge -2\}<em> and </em>\{x:-4 < x \ge 6\}<em>.</em>
  • <em>See attachmen</em>t for the graphs

The following should be notated when plotting the graph of an inequality

  • < and > are represented with open circles, while \leq and \geq are represented with closed circles
  • The arrows of and \le point to the left, while the arrows of > and \geq point to the right.

So, we have:

(a)\ -8 < x

Rewrite as:

x > -8

The graph of x > -8 will point to the right, and it will use an open circle

(b)\ -6 > x \ge -2

Split the inequality:

-6 > x and x \ge -2

<em>It is not possible for -6 to be less than x and at the same time, x is greater than or equal to -2.</em>

<em />

Hence. -6 > x \ge -2 cannot be represented on a graph

(c)\ -4

Split the inequality:

-4 < x and x \ge 6

-4 < x means that -4 is less than x or x is greater than -4.

So, we have:

x > -4 and x \ge 6

If x > -4 and x \ge 6, then we make use of x > -4 because it contains more values of x.

The graph of x > -4 will point to the right, and it will use an open circle

Read more about inequalities at:

brainly.com/question/11612965

6 0
3 years ago
Ind the equation of the tangent line to 9x^2+16y^2=52 through (2, -1)
EastWind [94]
Here are the steps.

In order to get the answer, first we need to get the x and y value of the center of the circle by using the equation of a circle (x^2 + y^2 = r^2)

<span>The center is (-9, -4)</span>

Once you get the center point, find the equation of the line (in a form of a radius) from the center point to point (2, -1). Get the slope.

The slope from center to point (2, -1) is 11/3

Finally, get the negative reciprocal of the slope from the previous step and form the equation using slope-intercept form ( y=mx + b). Then, that's the equation of the tangent line.

The slope of the tangent line is -3/11
The equation is y = -3/11x - 5/11

6 0
3 years ago
HELP PLEASE! Can you please explain so I can understand how it was completed?
nlexa [21]

Answer:

(3 square root of 2 , 135°), (-3 square root of 2 , 315°)

Step-by-step explanation:

Hello!

We need to determine two pairs of polar coordinates for the point (3, -3) with 0°≤ θ < 360°.

We know that the polar coordinate system is a two-dimensional coordinate. The two dimensions are:

  • The radial coordinate which is often denoted by r.
  • The angular coordinate by θ.

So we need to find r and θ. So we know that:

r=\sqrt{x^{2}+y^{2}}       (1)

x = rcos(θ)                                   (2)

x = rsin(θ)                                    (3)

From the statement we know that (x, y) = (3, -3).

Using the equation (1) we find that:

r=\sqrt{x^{2}+y^{2}}=\sqrt{3^{2}+(-3)^{2}} = 3\sqrt{2}

Using the equations (2) and (3) we find that:

3 = rcos(θ)

-3 = rsin(θ)

Solving the system of equations:

θ= -45

Then:

r = 3\sqrt{2}[/tex]

θ= -45 or 315

Notice that  there are two feasible angles, they both have a tangent of -1. The X will take the positive value, and Y the negative one.

So, the solution is:

(3 square root of 2 , 135°), (-3 square root of 2 , 315°)

4 0
3 years ago
What is the value of x?<br><br> 3 • (–4) • x = 0<br><br> x =
dedylja [7]
Multiply out
remember thatn (-) times (+)=(-) so
+3 times -4=-12
-12x=0
the only number that will work is 0 since 0 times anything=0

x=0
5 0
3 years ago
Read 2 more answers
Cos(7π/6)= a. 1/2 b.-1/2 c.√3/2 d.-√3/2 Help please?
olga nikolaevna [1]

Answer:

D. -√3/2

Step-by-step explanation:

Remember your unit circle.

Alternatively, you can plug in cos(7π/6) into your calc (Put it in rad mode) and calculate your answer.

3 0
3 years ago
Read 2 more answers
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