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REY [17]
3 years ago
7

The fraction subtracted from 5/3 to get 1 is_____​

Mathematics
2 answers:
siniylev [52]3 years ago
7 0

Answer:

2/3

Step-by-step explanation:

I am not sure

Sladkaya [172]3 years ago
6 0

Answer:

<h2>2/3</h2>

Step-by-step explanation:

Let  \:the \: unknown \: fraction \: be \: x\\\\\frac{5}{3} -x = 1\\\\\frac{5}{3}-x=1\\\\\mathrm{Subtract\:}\frac{5}{3}\mathrm{\:from\:both\:sides}\\\\\frac{5}{3}-x-\frac{5}{3}=1-\frac{5}{3}\\\\\frac{5}{3}-x-\frac{5}{3}=-x\\\\1-\frac{5}{3}=-\frac{2}{3}\\-x=-\frac{2}{3}\\\\x=\frac{2}{3}\\

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Using the picture below, which angle is alternate interior to angle 5?
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Answer:

angle 4

Step-by-step explanation:

Angle 4 is the opposite of angle 5, if you flip the paper upside down, you'll see that it is the same

7 0
2 years ago
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Arrange the following in descending order A] 9,7,4,1 B] 5,4,0,3
Masja [62]
A. correct as it is
B. 5, 4, 3, 0
5 0
3 years ago
For 300 trading​ days, the daily closing price of a stock​ (in $) is well modeled by a Normal model with mean ​$196.99 and stand
KATRIN_1 [288]

Answer:

a) 2.5% b) 84% c) 95% d) D. The more unusual day is if the stock closed below $185 because it has the largest absolute z-score.

Step-by-step explanation:

For a) b) and c) we will use the empirical rule, so, we can observe the image shown below

a) 211.23 is exactly two standard deviation above the mean, so, the probability that on a randomly selected day in this period the stock price closed above 211.23 is 2.35% + 0.15% = 2.5%  

b) 204.11 represents exactly one standard deviation above the mean, so, the probability of being below 204.11 is 50% + 34% = 84%

c) The probability of getting a value between 182.75 and 211.23 is 95%, this because 182.75 is exactly two standard deviations below the mean and 211.23 is exactly two standard deviations above the mean.

d) The z-score related to 208 is z_{1} = (208-196.99)/7.12 = 1.5 and the z-score related to 185 is  z_{2} = (185-196.99)/7.12 = -1.7, therefore, the more unusual day is if the stock closed below $185 because it has the largest absolute z-score.

5 0
3 years ago
PLEASE HELP ITS DUE TODAY!
Anton [14]

Answer:

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3 0
3 years ago
Solve the following triangle. Given A=51 degrees b=40 c=45
STALIN [3.7K]

Answer:

a=36.87\ units

B=57.47^o

C=71.53^o

Step-by-step explanation:

step 1

Find the length side a

Applying the law of cosines

a^2=b^2+c^2-2(b)(c)cos(A)

substitute the given values

a^2=40^2+45^2-2(40)(45)cos(51^o)

a^2=1,359.4466

a=36.87\ units

step 2

Find the measure of angle B

Applying the law of sines

\frac{a}{sin(A)} =\frac{b}{sin(B)}

substitute the given values

\frac{36.87}{sin(51^o)} =\frac{40}{sin(B)}

sin(B)=\frac{sin(51^o)}{36.87}{40}

B=sin^{-1}(\frac{sin(51^o)}{36.87}{40})=57.47^o

step 3

Find the measure of angle C

Remember that the sum of the interior angles in any triangle must be equal to 180 degrees

so

A+B+C=180^o

substitute the given values

51^o+57.47^o+C=180^o

108.47^o+C=180^o

C=180^o-108.47^o=71.53^o

5 0
3 years ago
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