We can use the FOIL method to simplify.
= (3x – 1)(2x + 9)
= (3x * 2x) + (3x * 9) + (-1 * 2x) + (-1 * 9)
= 6x + 27x + (-2x) + (-9)
= 33x - 11
Hope This Helped! Good Luck!
Answer:
Margret need to get 4 boxes of cookies.
Step-by-step explanation:
Total friends = 3
Cookies each friend will get = 8
Each box has cookies = 6 cookies
How many boxes does Margret need to get?
Total cookies will be= Total friends x Cookies each friend will get
Total cookies will be= 3 x 8 = 24
If one box has 6 cookies and we need total 24 cookies so, divide 24 by 6 to get number of boxes
Number of boxes = Total cookies/ number of cookies in one box
Number of boxes = 24/6
Number of boxes = 4
So, Margret need to get 4 boxes of cookies.
Answer:
5 , -7 , 10
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given
- 
× - 
( negative times negative = positive )
= × ( cancel the 4 on the numerator and denominator )
=
<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> )
<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> ) × (-1 + <em>i</em> ) / (-1 + <em>i</em> )
<em>z</em> = (3<em>i</em> × (-1 + <em>i</em> )) / ((-1)² - <em>i</em> ²)
<em>z</em> = (-3<em>i</em> + 3<em>i</em> ²) / ((-1)² - <em>i</em> ²)
<em>z</em> = (-3 - 3<em>i </em>) / (1 - (-1))
<em>z</em> = (-3 - 3<em>i </em>) / 2
Note that this number lies in the third quadrant of the complex plane, where both Re(<em>z</em>) and Im(<em>z</em>) are negative. But arctan only returns angles between -<em>π</em>/2 and <em>π</em>/2. So we have
arg(<em>z</em>) = arctan((-3/2)/(-3/2)) - <em>π</em>
arg(<em>z</em>) = arctan(1) - <em>π</em>
arg(<em>z</em>) = <em>π</em>/4 - <em>π</em>
arg(<em>z</em>) = -3<em>π</em>/4
where I'm taking arg(<em>z</em>) to have a range of -<em>π</em> < arg(<em>z</em>) ≤ <em>π</em>.
