<span>The answer to this problem is B. t – 51 = 127 t = 178 $178.</span>
<span>1/2x+3y/4=5 => (1/2)x + (3/4)y = 5
1/5x+3y/2=2 => (1/5)x + (3/2)y = 2
Eliminate the fractional coefficients: Mult. the first equation by 4 and mult. the second equation by 10:
2x + 15y = 20
</span><span>Multiply the 1st equation by -1:
-</span>2x - 3y = -20
2x + 15y = 20
-------------------
12y = 0, so y = 0. Then the first equation becomes 2x + 3(0) = 20, or
x=10.
Solution is (10,0).
1. 700 calories
2. Half a serving
3.x=serving
350x=calories
Answer:
wait.. almost done...
Step-by-step explanation:
2[5+2(8-6)]
2[5+2(2)]
2[5+4]
2[9]
18
