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goldenfox [79]
3 years ago
6

The maximum contaminant level of copper (Cu) in drinking water as set by the the Environmental Protection Agency (EPA) is 0.0013

g⋅L−1 . Express this concentration in parts per million (ppm). Assume the density of water is 1.00 g/mL .
Chemistry
1 answer:
Mazyrski [523]3 years ago
4 0

Answer is: concentration is 1.3 ppm.

Parts-per-million (10⁻⁶) is present at one-millionth of a gram per gram of sample solution, for example mg/kg.

d(Cu) = 0.0013 g/L; mass concentration of copper.

d(H₂O) = 1.00 g/mL; density of water.

m(H₂O) = V(H₂O) · d(H₂O).

m(H₂O) = 1000 mL · 1 g/mL.

m(H₂O) = 1000 g ÷ 1000 g/kg.

m(H₂O) = 1 kg; mass of water.

m(Cu) = 0.0013 g · 1000 mg/g.

m(Cu) = 1.3 mg; mass of coppper.

concentration = 1.3 mg ÷ 1 kg.

concentration = 1.3 mg/kg.

concentration = 1.3 ppm.

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