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valkas [14]
3 years ago
12

1. What will happen if a car experiences a 300 N force to the right from the engine and a separate 150 N force due to friction a

nd air resistance to the left? Show your work to support your position.
Chemistry
1 answer:
zavuch27 [327]3 years ago
4 0

<u>Given:</u>

Force acting on the car moving it to the right = F1= 300 N

Force due to friction and air resistance moving it to the left = F2 = 150 N

<u>To determine:</u>

The net force on the car

<u>Explanation:</u>

Force is a vector. The force of friction acts in a direction opposite to the applied force.

If, F1 = 300N, right, then F2 = -150 N, left

Therefore, the net force acting on the car will be:

F = F1+F2 = 300 - 150 = 150 N

<u>Ans</u>: Since the force acting on the right is greater, the car will experience a net force of 150 N which will accelerate it to the right

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As the world changes, plants and animals change with it. Aside from a few living fossils, the species we see today are very different from species that lived in the past. Thus, the fossil record can be used to show that organisms changed to meet new conditions. This is the result of evolution of species over time.

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2 years ago
When a solution of 0.1 M Mg(NO3)2 was mixed with a limited amount of aqueous ammonia, a light white, wispy solid was observed, i
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<u>Answer:</u> The net ionic equation is written below.

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

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The chemical equation for the reaction of magnesium nitrate and aqueous ammonia (ammonium hydroxide) is given as:

Mg(NO_3)_2(aq.)+2NH_4OH(aq.)\rightarrow Mg(OH)_2(s)+2NH_4NO_3(aq.)

A white precipitate of magnesium hydroxide is formed in the above reaction.

Ionic form of the above equation follows:

Mg^{2+}(aq.)+2NO_3^-(aq.)+2NH_4^+(aq.)+2OH^-(aq.)\rightarrow Mg(OH)_2(s)+2NH_4^+(aq.)+2NO_3^-(aq.)

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Mg^{2+}(aq.)+2OH^-(aq.)\rightarrow Mg(OH)_2(s)

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3 years ago
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4 0
3 years ago
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