Line D and C because they are not parallel but distorted or unsymmetrical
diameter is 15 meters then radius is 15/2 = 7.5 meters
so the amplitude is 7.5 m and height will oscillate with amplitude 7.5 m above and below the center.
midline of the oscillation will be 7.5 m
the wheel.take 8 minutes to complete revolution then it means the height will oscillate with a period of 8 minutes
To find how much Henry can expect to receive from Social Security on a monthly basis, we first need to find how much he cant expect to receive from social security per year.
We know form our problem that Henry averaged an annual salary of $45,620, so to find how much can Henry expect to receive from Social Security per year, we just need to find the 42% of $45,620.
To find the 42% of $45,620, we are going to convert 42% to a decimal by dividing it by 100%, and then we are going to multiply the resulting decimal by $45,620:

Social security annual payment = (0.42)($45,620) = $19,160.40
Since there are 12 month in a year, we just need to divided the social security annual payment by 12 to find how much he can expect to receive each month.
Social security monthly payment =
= $1.596.70
We can conclude that Henry can expect to receive $1.596.70 monthly from Social Security.
Using the normal distribution, it is found that there is a 0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
In this problem, the mean and the standard deviation are given, respectively, by:
.
The probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters is <u>one subtracted by the p-value of Z when X = 4</u>, hence:


Z = 1.71
Z = 1.71 has a p-value of 0.9564.
1 - 0.9564 = 0.0436.
0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.
More can be learned about the normal distribution at brainly.com/question/24663213
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