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igomit [66]
3 years ago
13

HELP

Mathematics
2 answers:
ad-work [718]3 years ago
7 0

this would be -7.2 and -0.8

hope this helps you out! good luck!

lora16 [44]3 years ago
4 0
-7.2 and -0.8 should be the correct answers
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What is the solution to the equation 1/square root of 8 = 4^(m + 2)?
Digiron [165]
Take the log (base 4) of both sides of the equation.
\log_{4}(\frac{1}{\sqrt{8}}) = m + 2
\frac{-1}{2} \log_{4}(4^{\frac{3}{2}})-2 = m
-2 \frac{3}{4}= m

The appropriate choice is ...
  m = -11/4
8 0
3 years ago
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The average weight of a newborn panda is 0.2, or 2/10 pound. Between what two integers is the weight of a newborn panda?​
sweet-ann [11.9K]

Answer:

\frac{2}{10} lies between 0 and 1.

Step-by-step explanation:

We must have in mind that given average weight of a newborn panda is a non-integer rational number, such that lies between two integer rational number. In other words, this number must satisfy the following condition:

n < \frac{a}{b} < n +1, n, a, b \in \mathbb{N}_{O}

\mathbb{N}_{O} = \mathbb{N}\,\cup\,{\{0\}}

Which is now developed mathematically to deduce a useful expression to find integers:

1) n < \frac{a}{b} < n +1 Given

2) n \cdot 1 < \frac{a}{b} < n\cdot 1 + 1 Modulative property

3) n \cdot (b\cdot b^{-1}) < a\cdot b^{-1} < n \cdot (b\cdot b^{-1}) + b\cdot b^{-1} Existence of Multiplicative inverse/Definition of division.

4) (n\cdot b)\cdot b^{-1} < a\cdot b^{-1}< [(n+1)\cdot b] \cdot b^{-1} Commutative, Associative and Distributive properties.

5) n\cdot b < a < (n+1)\cdot b Compatibility with Multiplication/Existence of Multiplicative Inverse/Modulative Property/Result.

If we know that a = 2 and b = 10, the following inequation is formed:

10\cdot n < 2 < 10\cdot (n+1)

It is quite evident to conclude that \frac{2}{10} lies between 0 and 1.

6 0
3 years ago
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Natalka [10]

Answer:

€295.2

Step-by-step explanation:

410x0.72 = 295.2

please mark brainliest

8 0
3 years ago
Which statements are true about these lines? Select three options.
shepuryov [24]
RS is perpendicular to MN and PQ.


We can use the slopes of these lines to determine the answer.
Slope is given by the formula
m=.

Using the coordinates for M and N, we have:
m=.

Since PQ is parallel to MN, its slope will be as well, since parallel lines have the same slope.

Using the coordinates for points T and V in the slope formula, we have
m=.

This is not parallel to MN or PQ, since the slopes are not the same.
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Using the coordinates for R and S in the slope formula, we have
m=. Comparing this to the slope of RS, it is flipped and the sign is opposite; they are negative reciprocals, so they are perpendicular.
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3 years ago
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Value of complex number i^7+1/i^4​
Vera_Pavlovna [14]

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7 0
3 years ago
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