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Alchen [17]
3 years ago
10

One thousand dollars is invested in a savings account that pays 9% interest per year. The interest earned after the first year i

s added to the account. How much interest is earned on the new principal the following year?
Mathematics
1 answer:
Ray Of Light [21]3 years ago
4 0
In order to solve this problem, the first thing we are going to do is find out how much is 9% of 1000, since 9% is the interest per year. So 0.09 x 1000 and that would be 90. And since the interest earned is added to the account, the account will now have a total of $1090 which is now the new principal. Based on this new principal, we need to know the 9% of it again to know how much interest in earned in the following year. So that would be 0.09 x 1090 and the result is $98.10. Hope this answer helps.
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Problems of normally distributed samples are solved using the z-score formula.

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In this problem, we have that:

\mu = 4.9, \sigma = 1.4

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This is the pvalue of Z when X = 3.

Z = \frac{X - \mu}{\sigma}

Z = \frac{3 - 4.9}{1.4}

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Z = -1.36 has a pvalue of 0.0869

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(b) the thickness is more than 7.0 mm

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0.0668 = 6.68% probability that the thickness is more than 7.0 mm

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hi

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