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Taya2010 [7]
3 years ago
9

What does constant of variation mean?

Mathematics
1 answer:
daser333 [38]3 years ago
8 0
The answer is C) A relationship between two quantities in which the ratio of one quantity to the other quantity is constant.

In other words,

The constant of variety is the number that is is comparable to two variables that are straightforwardly corresponding or contrarily corresponding to each other.

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Identify the slope type of the graph shown above.
Contact [7]
Answer is B. Zero
Reason
Pick any points on that line, they will have the same y value , it means they lie on a horizontal line. The slope of such a line is 0.
5 0
1 year ago
3 is the____ term<br><br>constant or variable ​
kherson [118]

\huge\mathcal\colorbox{yellow}{{\color{blue}{AnSwEr~↓~↓~}}}

\huge\mathbb\colorbox{black}{\color{white}{constant}}

7 0
3 years ago
Read 2 more answers
kathy is packing her suitcase for a trip. she wants the total weight of the suitcase to be no more than 50 pounds. the total wei
never [62]
D is the correct answer.

We do not need math in this instance, just knowledge.
We know that the answer will point to 0, not infinity. There are constraints. Also note that 1.75*7=12.25, which means you can fit no more than 7 books in the bag.
What best describes this? Answer Choice D
7 0
3 years ago
Which coin has a diameter with a 5 in the hundredths place?
Alexus [3.1K]
It would be both the penny and the quarter.

The hundredth place would be the third one from the left.

_._ _ _

So therefore the quarter and penny both have a five in that spot.
4 0
3 years ago
The diameter of a iron sphere is 8 cm. It is beaten and drawn into a wire with a diameter of 2 mm. Find the length of the wire.
djyliett [7]

Answer : The length of the wire is, 8533 cm

Step-by-step explanation :

As the iron sphere is beaten and drawn into a wire. That means, their volume will be equal.

Volume of iron sphere = Volume of cylindrical wire

The formula will be:

\frac{4}{3}\pi r_1^3=\pi r_2^2h

where,

r_1 = radius of sphere = \frac{Diamtere}{2}=\frac{8cm}{2}=4cm

r_2 = radius of cylindrical wire = \frac{Diamtere}{2}=\frac{2mm}{2}=1mm=0.1cm

h = height of cylindrical wire or length of wire

Now put all the given values in the above formula, we get:

\frac{4}{3}\pi r_1^3=\pi r_2^2h

\frac{4}{3}\times r_1^3=r_2^2h

\frac{4}{3}\times (4)^3=(0.1)^2h

h=8533.33cm\approx 8533cm

Therefore, the length of the wire is, 8533 cm

6 0
3 years ago
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