I can answer it but is the “S” supposed to be an integral?
Given that
log (x+y)/5 =( 1/2) {log x+logy}
We know that
log a+ log b = log ab
⇛log (x+y)/5 =( 1/2) log(xy)
We know that log a^m = m log a
⇛log (x+y)/5 = log (xy)^1/2
⇛log (x+y)/5 = log√(xy)
⇛(x+y)/5 = √(xy)
On squaring both sides then
⇛{ (x+y)/5}^2 = {√(xy)}^2
⇛(x+y)^2/5^2 = xy
⇛(x^2+y^2+2xy)/25 = xy
⇛x^2+y^2+2xy = 25xy
⇛x^2+y^2 = 25xy-2xy
⇛x^2+y^2 = 23xy
⇛( x^2+y^2)/xy = 23
⇛(x^2/xy) +(y^2/xy) = 23
⇛{(x×x)/xy} +{(y×y)/xy} = 23
⇛(x/y)+(y/x) = 23
Therefore, (x/y)+(y/x) = 23
Hence, the value of (x/y)+(y/x) is 23.
Answer:
-1
Step-by-step explanation:
x-2 = -3
x=-1
answer is negative one
(x+3)/2x+5 + (3x-5)/(3x+5)
LCM = ( 2x+5)( 3x+5)
[( x+3)( 3x+5) + ( 3x -5)( 2x+5)]/( 2x+5)( 3x+5)
= (3x^2 + 5x +9 x +15 + 6x^2 + 15x -10x -25)/( 2x+5)( 3x+5)
=( 9 x^2 + 19x -10)/( 2x +5)(3x+5)
A) option
4% Bc it don’t enough France people in the country and the shareholding
