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Liula [17]
3 years ago
11

To maintain creditworthiness, individuals should _____.

Business
2 answers:
kirza4 [7]3 years ago
7 0
Use credible sources and never be biased or add opinion to an article meant to be purely factual.
vaieri [72.5K]3 years ago
4 0

-protect their credit card and account numbers to prevent unauthorized use

-quickly report lost or stolen credit cards

-look for credit cards that have no annual fees and lower interest rates

-read the terms of the credit carefully and make informed decisions

-pay off their total balance each month

-don't spend more than their credit limit

all this are answers hope helps.....

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Melanie graduated from the College of Business at the University of Arizona. What type of higher education Institution did she a
Rom4ik [11]
She attended a university
8 0
3 years ago
A local county is considering purchasing some dump trucks for the trash pickups. Each truck will cost $55,000 and have an operat
lianna [129]

Answer:

35,972

Explanation:

The equivalent annual cost can be calculated dividing NPV by the annuity factor

In order to find NPV first

                                   Year1    Year2   Year3   Year4  Year5         Total

Operating and

Maintenance              18000 21000  24000  27000 30000          -

Discount factor(10%)  0.909   0.826   0.751   0.683   0.620           -

Discounted CFs          16362   17346  18024    18411   18600      88,713

Salvage                                                                          12000  

Discount factor(10%)                                                     0.620

Discounted salvage                                                      7440        (7440)

Inital Cost                   (55,000)                                                      (55,000)

NPV                                                                                                136,333

Calculation for EAC

NPV = 136,333

Annuity factor for 5 years = 3.790

Equivalent annual cost = NPV /Annuity factor

Equivalent annual cost = 136,333/3.790

Equivalent annual cost = 35,972

8 0
3 years ago
What is the term that describes the spreading of materials, money, and human resources to get work done in the most economical a
Butoxors [25]
Resource allocation - Apex answer

6 0
3 years ago
Read 2 more answers
Benefits of delocalisation of firms​
inna [77]

Answer

It encourages the establishment of support business enterprises

Explanation:

This promotes national attachment and solidarity; and furthermore diminishes provincial urban relocation. Market for crude materials: localization makes showcase for privately delivered crude materials in this way making work and winning makers pay.  

When numerous organizations are situated in one locale, foundations, for example, banks, insurance agencies, and merchants are probably going to set up organizations in the region to offer administrations required  

Production of a pool of work: When ventures are moved in one zone, individuals will, in general, relocate to that district looking for business along these lines empowering the making of a pool of work power.

6 0
3 years ago
Suppose 20.0 g pieces of gold and iron, both initially at 100oC, are added to different containers of water, both initially at 2
Sauron [17]

Answer:

  • The final temperature in the container with Gold is 27.49 ⁰C
  • The final temperature in the container with Iron is  33.01  ⁰C

Therefore, the highest final temperature is obtained in the container with Iron.

Explanation:

Q = mcΔT

Where;

Q is the quantity of heat gained or lost

m is the mass of the metals or water

c is the specific heat capacity

ΔT is the change in temperature, T₂ - T₁

T₂  is the final temperature and T₁ is the initial temperature

Heat lost by metals at 100°C is equal to heat gained by water at 25°C

-Q_{metal} = Q_{water}

-Q_{Au} = Q_{H_2O} \\-Q_{Fe}  = Q_{H_2O}

Specific heat capacity of water = 4.18 J/g°C

Specific heat capacity of gold = 0.129 J/g°C

Specific heat capacity of iron  = 0.45 J/g°C

⇒For Gold

-20*0.129*(T₂ - 100) = 18*4.18 (T₂ - 25)

-2.58T₂ +258 = 75.24T₂  - 1881

77.82T₂  = 2139

T₂  = 2139/77.82

T₂ = 27.49 ⁰C

⇒For Iron

-20*0.450*(T₂ - 100) = 18*4.18 (T₂  - 25)

-9T₂  +900 = 75.24T₂ - 1881

84.24T₂ = 2781

T₂  = 2781/84.24

T₂ = 33.01  ⁰C

Therefore, the highest final temperature is obtained in the container with Iron.

5 0
3 years ago
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