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Arturiano [62]
3 years ago
10

Help me please I don’t understand

Mathematics
2 answers:
riadik2000 [5.3K]3 years ago
6 0

Answer:

0.75 (45 mins) for both

Step-by-step explanation:

It's because the rest is the time where no activity is happening (the straight line). That line when measured from its start to end is mins 45 to mins 90, and when subtracted, gives 45 mins. For the initial ride it is from where the line moves upward until it stops. That goes from mins 0 to mins 45 ad when subtracted gives 45 mins.

sashaice [31]3 years ago
4 0

Answer:

She stopped to rest for 45 minutes.

Step-by-step explanation:

It's where the line is straight. What's the second question?

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A. it forms a triangle

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What is the equation of the line that passes through the point (-1,7) and is parallel to the line y= -2x-1
Nuetrik [128]

if we look at the equation y = -2x - 1, is already in slope-intercept form, therefore, \bf y=\stackrel{slope}{-2}x-1 has a slope of -2.


now, parallel lines have exactly equal slopes, therefore a parallel to that one above, will have also a slope of -2, so we're really looking for a line whose slope is -2 and runs through -1, 7.


\bf (\stackrel{x_1}{-1}~,~\stackrel{y_1}{7})\qquad \qquad \qquad slope =  m\implies -2\\\\\\\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-7=-2[x-(-1)]\\\\\\y-7=-2(x+1)\implies y-7=-2x-2\implies y=-2x+5

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3 years ago
Jane gets a simple interest loan for $2500. If the bank charges 3% interest rate how much will her balance be after 5 years?
Degger [83]
2500 divided by 100 is 25. If you multiply 25 times 3 you'll get 75. Repeat those steps (answers will be different each time) five times. You will get the answer.

Don't want to do that? OK! I'll do it for you!

Answer: <span>2577.31958575</span>
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It costs $12 to place 8 lines of copy in a local advertising circular . What is the unit rate per line
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7 0
3 years ago
How do you rearrange formulae???
Romashka-Z-Leto [24]

Answer:

  make use of the properties of equality of of inverse functions and operations

Step-by-step explanation:

In algebra, each of the operations and functions we study has an inverse. As a rule, in any "solve for ..." situation, you want to "undo" the operations and functions performed on the variable of interest. You can use the Order of Operations to determine the order those operations are performed, then <em>undo them in reverse order</em>.

<u>Trivial example</u>:

  Solve x + 3 = 5 for x. We observe that the variable x has had 3 added to it. We "undo" the addition of 3 by adding its opposite, -3. The properties of equality require that we add this value to both sides of the equation:

  x +3 -3 = 5 -3

  x = 2 . . . . . after simplification

__

Rearranging also involves combining terms, finding a common denominator, rationalizing denominators, and similar algebraic operations. These sorts of operations are performed on variables and expressions in virtually the same way they are performed on numbers.

<u>Less trivial example</u>:

Suppose we have the equation of a circle, and we want to rearrange it to find an expression for y.

  (x -h)^2 +(y -k)^2 = r^2

We observe that y has k subtracted, the result is squared, and an x-term is added. Undoing these in reverse order means we first subtract the x-term, then take the square root, and finally add k.

  (y -k)^2 = r^2 -(x -h)^2 . . . . . . we subtracted the x-term from both sides

  y -k = √(r^2 -(x -h)^2) . . . . . . and took the square root. Notice we have retained only the positive square root, so the bottom half of the circle will go missing from our final equation.

  y = k + √(r^2 -(x -h)^2) . . . . . finally, we added k

This is the formula for a circle rearranged to find y in terms of x. The value of y is that associated with the top half of the circle. If we want the bottom half, we must negate the square root:

  y = k - √(r^2 -(x -h)^2) . . . . . . formula rearranged to give the bottom half

Note that the root function is used to "undo" the operation of raising to a power. As we said, each of the operations we study in algebra has its "undo". It is useful to pay attention to the inverse operation associated with any new operation or function you learn about. (trig functions, log functions, exponentiation come to mind)

3 0
3 years ago
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