The answer is C, 2/3. 1, 3, 5, 6, 7, 9, 11, and 12 are possible draws. 8/12 is equal to 2/3!
I'm assuming no air friction here, first use conservation of energy to find velocity, so initially all the energy is from the spring, (1/2)kx^2, then it is converted to kinetic energy, (1/2)mv^2. so .5kx^2=.5mv^2. the .5s cancel, kx^2=mv^2. solve for v, v=sqrt(kx^2/m) plug in your values for the variables and find v. then use vf^2=vi^2+2ax in the u direction and solve for vf, vf=sqrt(vi^2+2ax). use that velocity in vf=vi+at and solve for t. vi=0 and a=g=9.81, so vf/a=t. plug in the values from the previous equation and the acceleration due to gravity to find the time it takes to hit the ground vertically. Now use v=x/t and solve for x. x=vt, plug in the velocity of the ball horizontally, which we found with the conservation of energy part, and y which we found with the previous equation, and you get your x, the distance it will take for the ball to hit the ground.
The train probably has glide reflection symmetry.
We have got an geometric progression.
We use to find any term of a geometric sequence, this equation:
an=a₁ * r^(n-1)
a₁= is the first term.
r=is the common ratio.
n=numbers of the term to find.
r=an / an-1
In this case:
r=a₂/a₁=(-4.8) / 9.6=-0.5
a₁=9.6
an=9.6*(-0.5)^(n-1)