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aleksandrvk [35]
3 years ago
10

If your bank offered you 3% interest on $5,000 in your savings account, how much money would you have in your account at the end

of the year after interest?
Mathematics
1 answer:
zimovet [89]3 years ago
6 0

Answer:

$150

Step-by-step explanation:

The formula we'll use for this is the simple interest formula, or: I= p * r * t

You might be interested in
What is the approximate total percent off when you buy something at "An extra 20% off of 40% off"?
Georgia [21]

Answer:

48%

Step-by-step explanation:

let's say the initial price of an item is $100

if you take 40% off then you pay only $60

now if you take 20% off 60 you pay $48

$48 is 48% of 100

8 0
3 years ago
The width of a rectangle is 9 in. shorter than its length. The area of the rectangle is 252 in². What is the length of the recta
erastovalidia [21]

Answer:

the length of the rectangle is, 21 in.

Step-by-step explanation:

Area of the rectangle(A) is given by:

A=lw           .....[1]

where,

l is the length of the rectangle

w is the width of the rectangle.

As per the statement:

The width of a rectangle is 9 in. shorter than its length.

⇒w = l-9

It is also given that:

The area of the rectangle is 252 in².

⇒A = 252  in².

Substitute in [1] we have;

252 = l(l-9)

⇒252 = l^2-9l

⇒l^2-9l -252 = 0

Factorize this equation:

Split the middle term;

⇒l^2-21l+12l-252=0

⇒l(l-21)+12(l-21)=0

⇒(l-21)(l+12)=0

By zero product property we have;

l-21 =0 and l+12 =0

⇒l = 21 and l = -12

Since, length cannot be in negative

⇒l = 21 in.

Therefore, the length of the rectangle is, 21 inches.

4 0
3 years ago
Suppose an unknown radioactive substance produces 8000 counts per minute on a Geiger counter at a certain time, and only 500 cou
mariarad [96]

Answer:

The half-life of the radioactive substance is of 3.25 days.

Step-by-step explanation:

The amount of radioactive substance is proportional to the number of counts per minute:

This means that the amount is given by the following differential equation:

\frac{dQ}{dt} = -kQ

In which k is the decay rate.

The solution is:

Q(t) = Q(0)e^{-kt}

In which Q(0) is the initial amount:

8000 counts per minute on a Geiger counter at a certain time

This means that Q(0) = 8000

500 counts per minute 13 days later.

This means that Q(13) = 500. We use this to find k.

Q(t) = Q(0)e^{-kt}

500 = 8000e^{-13k}

e^{-13k} = \frac{500}{8000}

\ln{e^{-13k}} = \ln{\frac{500}{8000}}

-13k = \ln{\frac{500}{8000}}

k = -\frac{\ln{\frac{500}{8000}}}{13}

k = 0.2133

So

Q(t) = Q(0)e^{-0.2133t}

Determine the half-life of the radioactive substance.

This is t for which Q(t) = 0.5Q(0). So

Q(t) = Q(0)e^{-0.2133t}

0.5Q(0) = Q(0)e^{-0.2133t}

e^{-0.2133t} = 0.5

\ln{e^{-0.2133t}} = \ln{0.5}

-0.2133t = \ln{0.5}

t = -\frac{\ln{0.5}}{0.2133}

t = 3.25

The half-life of the radioactive substance is of 3.25 days.

7 0
3 years ago
Hmmmm-Another one please?
Lubov Fominskaja [6]

Answer:

24

Step-by-step explanation:

Find the number that 9 multiplies by to get 54

so

9x6=54

do the same to four

4x6=24

Or

cross multiply

Lets put N as the missing number

4x54=9xN

Solve

216=9N

24=N

6 0
2 years ago
Read 2 more answers
I need help! ill give brainliest! please!
Serggg [28]
How explain please !!!!!!!!!!
4 0
3 years ago
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