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Svetlanka [38]
3 years ago
9

Norton can mow the large lawn in about 5 hours. When he works with

Mathematics
1 answer:
astra-53 [7]3 years ago
5 0

Answer:

7.5 hours

Step-by-step explanation:

The key here is to find out how much can be done in the same amount ot time

the least common multiple of 5 hrs and 3 hrs is 15hrs

In 15 hours:

- At 5 hours per lawn Norton could mow 15/5 = 3 lawns

- At 3 hours per lawn together thay could mow 15/3 = 5 lawns

In 15 hours Jesse would mow 5 - 3 = 2 lawns

15 hours/ 2 lawns = 7.5 hours per lawn

7.5 hours

--------------------

Here's the math

1 lawn/5hrs + x = 1 lawn / 3hrs

1/5 + x = 1/3

Subtract 1/5 from both sides

x = 1/3 - 1/5

x = 5/15 - 3/15

x = 2/15

x = 2lawns/15 hrs

15hrs/2lawns = 7.5 hrs per lawn

7.5 hours

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Answer:

G. y=2x-5

Step-by-step explanation:

First, find the slope from 2x-y=-3

-y=-2x-3

y=2x+3, which means that the slope is 2

Since it is parallel, the given equation and the line we are finding has the same slope.

let y=mx+b, where m=2, y=5, x=5

5=2(5)+b

5=10+b

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Answer:

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y \alpha x \\ y = kx \\ where \: k \: is \: the \: constant \: of \: proportionality \\ when \: y = 24 \: and \: x = 8 \\ substitute \: in \: y = kx \\ 24 = 8k \\ k =  \frac{24}{8}  \\ k = 3 \\ value \: of \: constant = 3

If it was by 10, k = 3 by 10

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5).

general \: equation \: of \: line  \\ y = mx + c \\ but \: m =  \frac{2}{3}  \: and \: c = 9 \\ substitute \: for \: m \: and \: c \: in \: y = mx + c \\ y =  \frac{2}{3} x + 9 \\ alternatively \\ 3y = 2x + 27

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3 years ago
Can someone plz help me with this problem and plz show work.
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Answer:

C

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y = 2x + 5

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