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svlad2 [7]
3 years ago
6

The base of a trinagle is increased by 20% and it’s height is increased by 30%. By what percent is the area of the triangle incr

eased?
Mathematics
1 answer:
Molodets [167]3 years ago
4 0

Lets say the base is x and the height is y. The new base would be 1.2x and the new height would be 1.3y

Area of a triangle is base times height divided by 2:

1.2x*1.3y/2 = (1.2*1.3 + x*y)/2 = 1.56xy/2 = 0.78xy = 78% of xy

But a normal area would be 50% of xy

78% - 50% = 38%

ANSWER: 38% increase

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⁵/₃ ln 2

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y = √x, y = 1

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Now we can rewrite the integral:

∫₀¹ ∫₀ʸ² 5 / (y³ + 1) dx dy

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Solve the integral.

∫₀¹ [ 5 / (y³ + 1) x |₀ʸ² ] dy

∫₀¹ [ 5y² / (y³ + 1) ] dy

⁵/₃ ∫₀¹ [ 3y² / (y³ + 1) ] dy

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⁵/₃ ln 2

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