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marin [14]
2 years ago
5

Ian worked 45 hours in a week, earning a total of $1101.60. He worked 35 hours normal time, 8 hours of time and a half and 2 hou

rs were double time. What is his normal hourly wage ?
(Show clear and easy working)
Mathematics
1 answer:
Fofino [41]2 years ago
3 0

Answer:

$21.6/hr

Step-by-step explanation:

Time paid

For 8 hours paid as 1.5, time is 8*1.5=12 hours

Similarly, for double hours, then it is 2*2=4

Given 35 normal hours, the total time will be the sum of 35, 12 and 4 hence 35+12+4=51 hours

Considering the pay of $1101.60 this is equivalent to hourly pay of 1101.60/51=21.6

Therefore, the hourly pay is $21.6 per hour

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-10w + 12 = -9w + 13<br> What value of w makes the equation true?
nika2105 [10]
W=-15 I hope this helped.
6 0
3 years ago
Which of these sequences is a geometric sequence?
Harman [31]

Answer:

d is right...............

5 0
3 years ago
Find the general indefinite integral. (use c for the constant of integration. )
Vlada [557]

The indefinite integral will be  \int (7x^2+8x-2)dx=\dfrac{7x^3}{3}+4x^2-2x+C)

<h3 /><h3>what is indefinite integral?</h3>

When we integrate any function without the limits then it will be an indefinite integral.

General Formulas and Concepts:

Integration Rule [Reverse Power Rule]:                                                              

\int x^ndx=\dfrac{x^{n+1}}{n+1}}+C

Integration Property [Multiplied Constant]:                                                        

\int cf(x)dx=c\int f(x)dx

Integration Property [Addition/Subtraction]:                                                      

\int [f(x)\pmg(x)]dx=\int f(x)dx\pm \intg(x)dx

[Integral] Rewrite [Integration Property - Addition/Subtraction]:

\int (7x^2+8x-2)dx=\int 7x^2dx+\int 8xdx    -\int 2dx          

[Integrals] Rewrite [Integration Property - Multiplied Constant]:  

\int (7x^2+8x-2)dx=7 \int x^2dx+ 8 \int xdx    -2\int dx            

[Integrals] Reverse Power Rule:    

\int (7x^2+8x-2)dx= 7(\dfrac{x^3}{3})+8(\dfrac{x^2}{2})-2x+C                                                            

Simplify:    

\int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C                                                                                                      

So the indefinite integral will be \int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C                

To know more about indefinite integral follow

brainly.com/question/27419605

#SPJ4

7 0
2 years ago
HELP ON THIS PROBLEM!!<br><br> Solve the following 0deg&lt; x&lt; 360deg: cos x= cos 2x
blsea [12.9K]

Answer:

x=0^\circ,120^\circ,240^\circ,360^\circ

Step-by-step explanation:

<u>Use identities to set the equation up as a quadratic</u>

\cos x=\cos 2x;\:0^\circ \leq x \leq 360^\circ\\\\\cos x=2\cos^2 x-1\\\\0=2\cos^2 x-\cos x-1

<u>Make the substitution u=cos(x) and solve the quadratic</u>

<u />0=2u^2-u-1\\\\0=(2u+1)(u-1)

\displaystyle 0=2u+1\\\\0=2\cos x+1\\\\-1=2\cos x\\\\-\frac{1}{2}=\cos x\\\\120^\circ,240^\circ=x

0=u-1\\\\0=\cos x-1\\\\1=\cos x\\\\0^\circ,360^\circ=x

Hence, x=0^\circ,120^\circ,240^\circ,360^\circ

7 0
1 year ago
Determine the next step for solving the quadratic equation by completing the square.
Lady_Fox [76]

Answer:

-7/2 = -2(x-1/2)^2

Step-by-step explanation:

0 = –2x^2 + 2x + 3

Subtract 3 from each side

-3 = –2x^2 + 2x

Factor out the -2

-3 =- 2(x^2 -x)

Take the coefficient of x and divide by 2 and square it

-1 /2 = -1/2 ^2 = 1/4

Add it to each side  Remember the -2 on the outside so we need to multiply it by -2  

-2 *1/4 =  -1/2

-3 -1/2= -2(x^2 -x +1/4)

-7/2 = -2(x^2 -x +1/4)

-7/2 = -2(x-1/2)^2

6 0
3 years ago
Read 2 more answers
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